0
3.8 grams of EDTA salt in 1 liter of DI water made up using a volumetric flask will give you 0.02n or 0.01m of EDTA solution.
normality*eq.wt*volume rqrd
weight= 1000
then will get weight of the compound required for that normality
Jaylin Konopelski
Wiki User
∙ 14y agoBy dilution.
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