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I am going to assume that your "exactly" has some reasonable leeway associated with it. Molar concentration = (no. of mols)/volume (in L). Therefore 4.75 M = (no of mols) /0.25 L Therefore no. of mols = 0.25 * 4.75 = 1.1875 mols Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol Therefore mass of 100 % NaOH required = 1.1875 mol * 40 g/mol =47.5 g NaOH So - in detail, you would weigh out the mass of solids NaOH, dissolve it in 250 ml of water and you would have the required solution. The volume won't be EXACT, but close as.
What else can I help you with?
How many milliliters of 6.0 M NaOH must be used to prepare 1.0 liter of 0.10 M solution?
To prepare a 0.10 M NaOH solution, you need to dilute the 6.0 M solution. You can use the formula: M1V1 = M2V2 where M1 = 6.0 M, V1 is the volume of 6.0 M NaOH needed, M2 = 0.10 M, and V2 = 1000 mL (1.0 L). By substituting the values into the formula, you can calculate the volume of the 6.0 M NaOH needed to prepare the 0.10 M solution.
How to prepare 6N NaOH?
To prepare a 6N NaOH solution, you would need to dissolve 240 grams of sodium hydroxide (NaOH) pellets in enough distilled water to make 1 liter of solution. This will result in a 6N (Normal) solution of NaOH. Remember to handle NaOH with caution as it is a strong base and can cause burns.
How many millilieters of 5.5 m naoh are needed to prepare 300 ml of 1.2 m naoh?
Use M1V1=M2V2 Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.
How do you prepare 1 L of 15 M sodium hydroxide solution by diluting the stock solution of 6 M sodium hydroxide?
To prepare 1 L of 15 M NaOH solution, you need to dilute the 6 M stock solution. You would need to take 500 mL of the 6 M NaOH stock solution and add water to bring the total volume up to 1 L. This will give you a final concentration of 15 M.
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
How many milliliters of 6.0 M NaOH must be used to prepare 1.0 liter of 0.10 M solution?
To prepare a 0.10 M NaOH solution, you need to dilute the 6.0 M solution. You can use the formula: M1V1 = M2V2 where M1 = 6.0 M, V1 is the volume of 6.0 M NaOH needed, M2 = 0.10 M, and V2 = 1000 mL (1.0 L). By substituting the values into the formula, you can calculate the volume of the 6.0 M NaOH needed to prepare the 0.10 M solution.
How to prepare 6N NaOH?
To prepare a 6N NaOH solution, you would need to dissolve 240 grams of sodium hydroxide (NaOH) pellets in enough distilled water to make 1 liter of solution. This will result in a 6N (Normal) solution of NaOH. Remember to handle NaOH with caution as it is a strong base and can cause burns.
How many millilieters of 5.5 m naoh are needed to prepare 300 ml of 1.2 m naoh?
Use M1V1=M2V2 Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.
Prepare 5 M NaOH of pH 12?
To prepare a 5 M NaOH solution, measure out 200 g of NaOH pellets and dissolve them in enough water to make 1 liter of solution. To adjust the pH to 12, you can titrate the solution with a standard acid solution (e.g. HCl) until the desired pH is reached. Remember to wear appropriate safety gear and use a fume hood when working with NaOH.
How many grams of of NaOH are required to prepare 200 mL of a 0.450 M solution?
Approximately 4.50 grams of NaOH are required to prepare 200 mL of a 0.450 M solution. This can be calculated using the formula: moles = Molarity x Volume (in L), and then converting moles to grams using the molar mass of NaOH.
How do you prepare 1 L of 15 M sodium hydroxide solution by diluting the stock solution of 6 M sodium hydroxide?
To prepare 1 L of 15 M NaOH solution, you need to dilute the 6 M stock solution. You would need to take 500 mL of the 6 M NaOH stock solution and add water to bring the total volume up to 1 L. This will give you a final concentration of 15 M.
27.0 ml of 0.45 m naoh is neutralized by 20 ml of an hcl solution the molarity of the hcl solution is?
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
How many moles of NaOH are needed to prepare 2 liters of a 2.0 M solution?
4 moles or 160 g NaOH is required for one litre solution.
How many milliliters of 0.400 M NaOH are required to completely neutralize 20.00 mL of 0.200 M HCl?
To neutralize HCl with NaOH, the mole ratio is 1:1. So, the moles of HCl are 0.200 M x 0.020 L = 0.004 moles. Since NaOH and HCl react in a 1:1 ratio, we need 0.004 moles of NaOH. Using the molarity formula, we find that we need 0.010 L or 10.00 mL of 0.400 M NaOH.
How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
Which has higher pH value 1M HCl or 1 M NaOH solution?
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
How many NaOH are needed to make 0.2 M of NaOH?
To make a 0.2 M solution of NaOH, you would need to dissolve 1 mole of NaOH in enough water to make a final volume of 1 liter. This corresponds to approximately 40 grams of NaOH.
