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Use M1V1=M2V2

Where M is the concentration (5.5 m for M1 and 1.2 m for M2) and V is volume V1 is 300 ml and V2 is your unknown. Using this calculation for other questions be sure that units are all the same. So all molarities and all mL in this example.

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Q: How many millilieters of 5.5 m naoh are needed to prepare 300 ml of 1.2 m naoh?
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How many moles of NaOH needed to prepare 300 mL of a 0.2 m solution of NaOH?

You need 2,4 g NaOH (0,06 moles).


How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?

Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.


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What volume of 2.5 M NaOH solution is required to prepare 2.0 liters of a 0.75M NaOH?

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How many grams of NaOH are needed to prepare 250ml of 0.205M NaOH?

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