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- Add 12,69 g iodine in 1 L water

- Add 20-30 g of potassium iodide, KI

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How many ml of 1 M stock solution of Na Cl are needed to prepare 200 ml of a 0.05 M solution?

Molartiy = moles of solute/Liters of solution200 mL X (1 Liter/10^2)= 0.200 Liters0.200 Liters x (0.05 M)= .01 moles of NaOH.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required


How do you prepare 0.5 N NaOH solution?

There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution


What pH of 4 is times more acidic as a pH of 7?

As the pH decreases, the solution becomes 10 times more acidic for each point. A solution of pH 4 is 10 times more acidic than a solution of pH 5. A solution of pH 3 is 10 times more acidic than a solution of pH 4. 10 x 10 = 100 A solution of pH 3 is 100 times more acidic than a solution of pH 5.


How would you make 100cm3 of 0 01 mol dm3 copper sulfate from a solution of 0 1 mol dm3 copper sulfate?

right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)


How much bleach in 20 gallon water to make 1 percent solution?

A one percent solution means 1 part beach and 99 parts water. So we can answer the question by solving the equation 1 part bleach/99 parts water=x gallons bleach/20 gallons water. You can cross multiply. This is the same as 99x=20 so x=20/99 or .20 Let's check .20 gallons bleach/ 20 gallons water=.01 which is 1% .2 gallons is the same as 3.2 cups or 25.6 fluid oz.

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How will prepare 200ml of 10 percent NaOH Solution?

Dissolve 0.4 g of NaOH in 100 ml of water. Try it out. Actually it is not suitable to prepare NaOH solutions in standard flasks.It should be made in beakers & must be standardised..This is done to find the correct normality...


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How many ml of 1 M stock solution of Na Cl are needed to prepare 200 ml of a 0.05 M solution?

Molartiy = moles of solute/Liters of solution200 mL X (1 Liter/10^2)= 0.200 Liters0.200 Liters x (0.05 M)= .01 moles of NaOH.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required


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644 Solution Method: 1% * 64400 = ? .01 * 64000 = 644


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This methodology is composed by six phases closely related: prepare, plan, design, implement, operate, optimize. More info on http://www.ciscozine.com/2009/01/29/the-ppdioo-network-lifecycle/ website


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What is the final concentration of cl- ion when 250 ml of 0.20 M cacl2 solution is mixed with 250 ml of 0.40 M kcl solution?

To find the final concentration of Cl- ions, first calculate the moles of Cl- ions from each solution. Then add the moles of Cl- ions from both solutions and divide by the total volume of the mixed solution (500 ml) to get the final concentration. Using the formula C1V1 = C2V2 where C represents concentration and V represents volume, you can determine the moles of Cl- ions from each solution.


How are volumes of hydrogen peroxide related to concentration of hydrogen peroxide expressed in percentage terms weight volume?

The strength of a solution may be described as a percentage or volume, where 1% hydrogen peroxide releases 3.3 volumes of oxygen during decomposition.Thus, a 3% solution is equivalent to 10 volume and a 6% solution to 20 volume, etc. Answer taken from Wikipedia 19/01/2009


How do you prepare 0.5 N NaOH solution?

There is 0.5 moles of NaOH per litre To calculate 0.5 molar NaOH first know the molecular weight of NaOH i.e 40 now multiply the number of moles of NaOH you have (0.5) found as above. so to find the number of grams of NaOH we needed to start with (0.5) * (40) = 20g So dissolve 20g of NaOH in one litre of the solution to prepare 0.5 molar solution