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0.4 M means 0.4 moles in 1 litre of water.
For Na2CO3 first calcultate the Relative Molecular Mass (Mr) from the Periodic Tabler.
2 x Na = 2 x 23 = 46
1 x C = 1 x 12 = 12
3 x O = 3 x 16 = 48
46 + 12 + 48 = 106
Next using the equation Moles = mass(g) / Mr
Algebraically rearrange
mass(g) = moles X Mr
mass ( g) = 0.4 X 106
mass( g) = 42.4 g
Weigh this amount out on a lab balance.
The dissolve in 500 mL of water.
When fully dissolved make the volume of the solution up to 1000 mL ( 1 litre) using distilled water.
NB Do NOT dissolve in 1000 mL(1 litre) as the volume in total will be greater than 1 litre, and it will not be 0.4 M , but a lesser value. Dissolve in less than 1 litre and make up to 1 litre with more distilled water.
NNB Finally, please write your chemical symbols correctly, 'Co' os the symbol for 'Cobalt'. For the Carbonate is is 'CO3'. Note the use of capitals.
Hope that helps!!!!
lenpollock
Wiki User
∙ 11y ago4.24 gm Na2CO3 IN 100 D.W.
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Why was 1.06 g of Na2 CO3 added to 1 liter if water to prepare a 0.02 n solution?
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
How do you prepare 250ml 15m solution of naco3 in a volumetric flask do presume a solvent ie h20 but then you have to presume volumes and conc and because 15M wanted you cant use the flask to dilute?
Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3
Sodium carbonate equation?
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
What is the AR or MR value of Co2 and NA2CO3?
ar of na2co3
How many grams are in 0.577 mol Na2CO3?
1 mole Na2CO3 = 105.98844g 0.577mol x 105.98844g/mol = 61.2g Na2CO3
How washing soda is prepared?
10 molecule of water is added to one molecule of Sodium carbonate to prepare washing soda. Na2CO3+10 H2O= Na2CO3 . 10 H2O
Why was 1.06 g of Na2 CO3 added to 1 liter if water to prepare a 0.02 n solution?
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
What are the merits and advantages of solvay's process?
The ingredients for the process are easily available and inexpensive.
How are 0.50m Na2CO3 and 0.50M Na2CO3 different?
difference between 0.50mol na2co3 anf 0.50 M of na2co3
How do you prepare 250ml 15m solution of naco3 in a volumetric flask do presume a solvent ie h20 but then you have to presume volumes and conc and because 15M wanted you cant use the flask to dilute?
Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3
Sodium carbonate equation?
The chemical formula of sodium carbonate is Na2CO3. A solution hasn't a formula.
Chemical formula of washing soda?
the chemical formula of washing soda is Na2CO3 (Sodium carbonate).
What is the AR or MR value of Co2 and NA2CO3?
ar of na2co3
What is the balanced equation of the reactants MnSO4 and Na2CO3?
MnSO4+Na2CO3
How many grams are in 0.577 mol Na2CO3?
1 mole Na2CO3 = 105.98844g 0.577mol x 105.98844g/mol = 61.2g Na2CO3
How many moles of washing soda are there in 5g?
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
What is the KB of Na2CO3?
The Kb of Na2CO3 is equal to 2.1 x 10^-4. Carbonate ion is the ion that results from the dissociation of Na2CO3.
