0.4 M means 0.4 moles in 1 litre of water.
For Na2CO3 first calcultate the Relative Molecular Mass (Mr) from the Periodic Tabler.
2 x Na = 2 x 23 = 46
1 x C = 1 x 12 = 12
3 x O = 3 x 16 = 48
46 + 12 + 48 = 106
Next using the equation Moles = mass(g) / Mr
Algebraically rearrange
mass(g) = moles X Mr
mass ( g) = 0.4 X 106
mass( g) = 42.4 g
Weigh this amount out on a lab balance.
The dissolve in 500 mL of water.
When fully dissolved make the volume of the solution up to 1000 mL ( 1 litre) using distilled water.
NB Do NOT dissolve in 1000 mL(1 litre) as the volume in total will be greater than 1 litre, and it will not be 0.4 M , but a lesser value. Dissolve in less than 1 litre and make up to 1 litre with more distilled water.
NNB Finally, please write your chemical symbols correctly, 'Co' os the symbol for 'Cobalt'. For the Carbonate is is 'CO3'. Note the use of capitals.
Hope that helps!!!!
To prepare a 0.1 N 100 ml Na2CO3 solution, dissolve 5.3 grams of Na2CO3 in water and dilute to 100 ml. This will give you a solution with a concentration of 0.1 normal (N) for the 100 ml volume.
To standardize an HCl solution with a primary standard Na2CO3 solution, first, prepare a Na2CO3 solution of known concentration. Then, titrate the Na2CO3 solution with the HCl solution using a suitable indicator until the equivalence point is reached. From the volume of HCl solution used and the known concentration of Na2CO3, you can calculate the exact concentration of the HCl solution.
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
To prepare a 2N solution of Na2CO3 in 500 mL, you would need to dissolve 42.97 grams of Na2CO3. This is calculated by first converting N to molarity (2N = 2 moles/L), then using the molar mass of Na2CO3 (105.99 g/mol) to calculate the required mass.
Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3
To prepare a 0.1 N 100 ml Na2CO3 solution, dissolve 5.3 grams of Na2CO3 in water and dilute to 100 ml. This will give you a solution with a concentration of 0.1 normal (N) for the 100 ml volume.
10 molecule of water is added to one molecule of Sodium carbonate to prepare washing soda. Na2CO3+10 H2O= Na2CO3 . 10 H2O
To standardize an HCl solution with a primary standard Na2CO3 solution, first, prepare a Na2CO3 solution of known concentration. Then, titrate the Na2CO3 solution with the HCl solution using a suitable indicator until the equivalence point is reached. From the volume of HCl solution used and the known concentration of Na2CO3, you can calculate the exact concentration of the HCl solution.
Molarity = moles of solute/Liters of solutionSo, get moles sodium carbonate.1.06 grams Na2CO3 (1 mole Na2CO3/105.99 grams)0.0100009435 moles Na2CO3----------------------------nowMolarity = 0.0100009435 moles Na2CO3/1 Liter= 0.01 M Na2CO3==============ask your teacher why because that much sodium carbonate does not have 0.02 molarity
To prepare a 2N solution of Na2CO3 in 500 mL, you would need to dissolve 42.97 grams of Na2CO3. This is calculated by first converting N to molarity (2N = 2 moles/L), then using the molar mass of Na2CO3 (105.99 g/mol) to calculate the required mass.
difference between 0.50mol na2co3 anf 0.50 M of na2co3
The ingredients for the process are easily available and inexpensive.
The balanced equation for the reaction between MnSO4 and Na2CO3 is: MnSO4 + Na2CO3 -> MnCO3 + Na2SO4.
the chemical formula of washing soda is Na2CO3 (Sodium carbonate).
Did you mean 250 mL of 0.15 M Na2CO3? (It's impossible to make a 15 M Na2CO3 solution, as Na2CO3 is not that soluble.) Yes, you can assume that this will be an aqueous solution. Steps. 1. Calculate the mass of solid Na2CO3 needed. 2. Place this mass of Na2CO3 in the volumetric flask. 3. Add some water and swirl to dissolve the Na2CO3. 4. Carefully add more water until the total volume of solution is 250 mL, as indicated by the line etched on the neck of the volumetric flask. 250 mL x 1 L x 0.15 mol Na2CO3 x 105.99 g Na2CO3 = 4.0 g Na2CO3 needed ........... 1000 mL ......... 1 L ..................1 mol Na2CO3
As far as I can tell from my research the 04m-497a is a version of the Mossberg 42. I've found a clip on http://www.gun-parts.com/mossberg/
50-200 USD