Make sure to use goggles and gloves, because sodium hydroxide is very caustic, and the mixture can get very hot (reaction is very exothermic).
1) Weigh out 400 grams (10 moles) of NaOH pellets.
2) Place 1 liter of water in a large borosilicate beaker (at least 2 liter volume) or other container that can handle very caustic substances.
3) Begin slowly adding NaOH pellets to your beaker or container and stirring. If using a glass container, you may want to have it set in an ice bath from the beginning to keep the temperature down, since the solution will begin to get hot as the sodium hydroxide dissolves. Continue until all of the pellets have dissolved in the 1 liter of water.
This will produce a 10 molar solution of NaOH.
Since 1 mole of NaOH dissociates in water to form 1 mole of Na+ ions and 1 mole of OH- ions, this will also produce a 10 N (in terms of normality) solution of NaOH.
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
To prepare a 1N NaOH solution from a 10N NaOH solution, you can dilute it by adding 1 part of the 10N NaOH solution to 9 parts of water. Measure the volume of the 10N NaOH solution needed based on the amount of 1N NaOH solution you want to prepare. Always add the concentrated solution to water slowly and mix well.
You need 400 g of solid NaOH dissolved in water and made up to exacly 1 liter in a volumetric flask. For 1 L solution: 1. Weight 399,9711 g of NaOH per analysis with an analytical balance. 2. Put the NaOH in a clean and dry Berzelius beaker. 3. Add very slowly and by stirring 500 mL water distilled (deionized); avoid the superheating. 4. Transfer quantitatively this solution in a 1 L volumetric flask. 5. Put the flask in a thermostat at 20 0C. 6. Wait for the temperature stabilization of the flask with the solution. 7. Add slowly distilled (deionized) water to the mark. 8. Stir the volumetric flask. 9. Put on the flask a label with: name of the reagent, concentration, date, operator.
weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.
To make 6N ammonium hydroxide solution, you can dilute a concentrated solution of ammonium hydroxide with water. For example, if you have a 10N solution, you can dilute it by adding water to reduce the concentration to 6N. Make sure to use proper safety precautions when handling chemicals.
To prepare a 6N NaOH solution from a 10N NaOH solution, you would dilute the 10N solution by adding water. Use the dilution formula: C1V1 = C2V2, where C1 is the initial concentration (10N), V1 is the volume of stock solution needed, C2 is the final concentration (6N), and V2 is the final volume of the solution you want to make. Calculate the volume of the 10N solution needed and add water to reach the final desired volume for a 6N NaOH solution.
To prepare a 1N NaOH solution from a 10N NaOH solution, you can dilute it by adding 1 part of the 10N NaOH solution to 9 parts of water. Measure the volume of the 10N NaOH solution needed based on the amount of 1N NaOH solution you want to prepare. Always add the concentrated solution to water slowly and mix well.
You need 400 g of solid NaOH dissolved in water and made up to exacly 1 liter in a volumetric flask. For 1 L solution: 1. Weight 399,9711 g of NaOH per analysis with an analytical balance. 2. Put the NaOH in a clean and dry Berzelius beaker. 3. Add very slowly and by stirring 500 mL water distilled (deionized); avoid the superheating. 4. Transfer quantitatively this solution in a 1 L volumetric flask. 5. Put the flask in a thermostat at 20 0C. 6. Wait for the temperature stabilization of the flask with the solution. 7. Add slowly distilled (deionized) water to the mark. 8. Stir the volumetric flask. 9. Put on the flask a label with: name of the reagent, concentration, date, operator.
weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution. Reasons:N is short for NORMAL SOLUTIONS, The definition of a NORMAL SOLUTION is a solution that contains 1 gram equivalent weight (gEW) per liter solution. An equivalent weight is equal to the molecular weight divided by the valence (replaceable H ions). eg:1N NaCl = 58.5 g/L 1N HCl = 36.5 g/L 1N H2S04 = 49 g/L Problems involving normality are worked the same as those involving molarity but the valence must be considered: 1N HCL the MW= 36.5 the EW = 36.5 and 1N would be 36.5g/L 1N H2SO4 the MW = 98 the EW = 49 and 1N would be 49 g/L 1N H3PO4 the MW = 98 the EW = 32.7 and 1N would be 32.7 g/L so,u can weigh out 365g of HCl pellets and dilute to 1 liter to prepare the 10N HCl solution.
If you're asking for a SOLUTION, 5 x 10n=0.005 => 50n=0.005 Divide 50 for the both side =>n=0.005/50.
10n=40
what is 10n=40
To solve the equation (10n = 36 - 2n), first, add (2n) to both sides to get (10n + 2n = 36), which simplifies to (12n = 36). Next, divide both sides by 12 to isolate (n), resulting in (n = 3). Thus, the solution to the equation is (n = 3).
10n is basically 10 times something. Example: 10n = 100/n=10
5n - 4 = 10n + 6-5n = 10n = -2
10n = 80.n = 8.
It is an expression in the form of: 10n-1