You need 400 g of solid NaOH dissolved in water and made up to exacly 1 liter in a volumetric flask.
For 1 L solution:
1. Weight 399,9711 g of NaOH per analysis with an analytical balance.
2. Put the NaOH in a clean and dry Berzelius beaker.
3. Add very slowly and by stirring 500 mL water distilled (deionized); avoid the superheating.
4. Transfer quantitatively this solution in a 1 L volumetric flask.
5. Put the flask in a thermostat at 20 0C.
6. Wait for the temperature stabilization of the flask with the solution.
7. Add slowly distilled (deionized) water to the mark.
8. Stir the volumetric flask.
9. Put on the flask a label with: name of the reagent, concentration, date, operator.
Dissolve 399,971 g NaOH in 1 L distilled water at 20 0C.
40 g of NaOH + 100 ml water
The dilution ratio is 1/10 (1 part 0,1 N solution mixed with 9 parts water).
It is possible only if you evaporate the water.
we need 0.8gm NaoH and dissolved in 10 ml of water to make 2N solution of NaoH .
1280 grams
12NHCL is not a chemical compound, maybe it is misspelled or incorrectly typed.
The dilution ratio is 1/10 (1 part 0,1 N solution mixed with 9 parts water).
10n=40
what is 10n=40
10n is basically 10 times something. Example: 10n = 100/n=10
5n - 4 = 10n + 6-5n = 10n = -2
NaOH and H2O form a solution of Na+(aq) and OH-(aq) ions (the solvent water, aq, is written as subscripted (aq) ) To make 1 Normal solution you need to know the equivalent of NaOH, which is calculated by dividing Molecular weight by 1, that is 40 divided by 1= 40. So the equivalent weight of NaOH is 40. To make 1 N solution, dissolve 40.00 g of sodium hydroxide in water to make volume of 1 liter.
It is an expression in the form of: 10n-1
10n = 80.n = 8.
It is possible only if you evaporate the water.
If: 10n = 1,000,000 Then: n = 100,000
10n + 3 = 93 Therefore, 10n = 90 n = 90/10 n = 9
1 foot = 12 inches so 10n feet = 10n*12 = 120n inches.