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Dissolve common salt in water. Aprroximately 6 grams in 100 mL of water,

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If you weighed 100 pounds on Earth you would weigh pounds on Saturn.?

106 pounds Saturn's gravity acceleration at the equator is about 10.4 m/s2. Earths gravity acceleration is 9.81 m/s2. So Saturn's gravity is about 10.4/9.81 = 1.06 times stronger than Earth's. That would put a weight of 100 lb on Earth, on 106 lb on the surface of Saturn at the equator.


Which car uses 106 alloys type wheels?

There are lots of different cars that use 106 Alloy type wheels. For example, there are many Peugeot cars that use 106 Alloy Type wheels, but also lots of Fords. A specific car that uses the 106 alloy wheels is the Honda Civic.


How many grams of calcium chloride needed to make 1.0 L of 200 ppm solution?

1 ppm = 1 mass part per 106 mass parts:So 1 mg in 106 mg = 1.0*106 mg = 1.0*103 g = 1.0 kg200 ppm = 200 mg per kg, in water 1.0 kg = 1.0 LitreSo 200 mg/L


What numbers are in the fact family of 106?

The fact family of 106 includes the numbers 106, 0, and 106. This is because you can create addition and subtraction equations such as 106 + 0 = 106 and 106 - 0 = 106. Additionally, if considering multiplication and division, the family could include the numbers 1 and 106, as in 1 × 106 = 106 and 106 ÷ 1 = 106.


What are 3 addition equations that have a solution of -6?

-3


What is the GCF of 1802 and 106?

The GCF is 106.


What is the scientific notation of 1600000?

It is 1.6*106.It is 1.6*106.It is 1.6*106.It is 1.6*106.


What is 86 percent of 106?

86% of 106= 86% * 106= 0.86 * 106= 91.16


What is 106 over 100 as a percentage?

percentage = 106%% rate:= 106/100 * 100%= 106%


Prepare a 1.00 L of a 0.25 M solution of sodium carbonate. Determine the amount of sodium carbonate needed in correct significant figures. A)21 g B)26 g C)332 g D)424 g?

To prepare a 1.00 L solution of 0.25 M sodium carbonate (Na₂CO₃), you can use the formula: [ \text{mass (g)} = \text{molarity (M)} \times \text{volume (L)} \times \text{molar mass (g/mol)} ] The molar mass of Na₂CO₃ is approximately 106 g/mol. Thus, the calculation is: [ 0.25 , \text{M} \times 1.00 , \text{L} \times 106 , \text{g/mol} = 26.5 , \text{g} ] Rounding to two significant figures gives 26 g, so the correct answer is B) 26 g.


How many ml of 110 M of HCl are needed to completely neutralize 54ml of 106 M of BaOH2 solution?

A concentration of 110 M or 106 M doesn't exist.


What is 135-106?

135-106 = 29