To separate a mixture of iodine and lead(II) nitrate, you can first dissolve the mixture in water to form a solution. Then, you can use techniques such as filtration or precipitation to separate the components. Lead(II) nitrate will precipitate out as a solid, while iodine remains in solution. You can then filter the solid lead(II) nitrate from the solution to isolate the two components.
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
It is aprecipitate chemical reaction.The chemical equation of aluminum iodide and leadII acetate is given as follows.. 2AlI3(aq) + 3Pb(C2H3O2)2(aq) --> 3PbI2(s) + 2Al(C2H3O2)3(aq).The above is a balanced equation.
First, balance the chemical equation to be Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3. Next, calculate the molar mass of NaI to be 149.89 g/mol. Use the stoichiometry to find the moles of NaI used, then use the coefficients to find the moles of PbI2 formed. Finally, calculate the mass of PbI2 formed, knowing its molar mass is 461.01 g/mol.
Pbl2
The chemical formula of lead(II) nitrate is Pb(NO3)2.
The chemical formula of lead(II) nitrate is Pb(NO3)2.
The correct formula for the product of lead(II) nitrate reacting with sodium iodide is lead(II) iodide, which has the formula PbI2. This is because lead(II) ions from lead(II) nitrate react with iodide ions from sodium iodide to form lead(II) iodide as the product.
Pb(NO3)2 + 2KCl ---> PbCl2 + 2KNO3
Formula: PbS
It would be: PbI2
PbBr2
Formula: PbO
Lead(II) Chromate = PbCrO4
This chemical formula is Pb3P2.
Pb(HSO4)2.