Cr2SO6
CrS3 is the formula of chromium(VI) sulfide
CrO3 is Chromium(VI) oxide also called Chromium trioxide
Chromium VI sulphate Cr(SO4)3
That would be chromium(IV) selenide with the formula CrSe2
Annon:The chemical formula of chromium II sulfate is CrSO4.Miki-San-X: ActuallySince this is probably Ionic naming since it starts with a metal and ends with a non metal you would take chromium (II) Sulfate and cross them-Like so-Start:Cr(II) SO4 (-2)We know that sulfate is SO4 with a -2 superscript and that chromium is a transition metal, but that it has a positive charge to counteract the negative charge of the -2.You will drop the charge and cross them-Cr2(SO4)2since you brought the -2 from the sulfate down to the chromium it becomes positive 2 because you dropped the charge before crossing. The reason you put the (SO4) in parenthesis is because you cannot, in a problem like this, have 42 next to your polyatomic ion. You have TWO of that ion, NOT 42.Hope I helped
CrS3 is the formula of chromium(VI) sulfide
That would be chromium(II) sulfate, but really, chromium mostly exists as Cr(III) or Cr(VI), which would change the formula.
Formula: CrP2
CrO3 is Chromium(VI) oxide also called Chromium trioxide
Chromium VI sulphate Cr(SO4)3
That would be chromium(IV) selenide with the formula CrSe2
No. CrS3 is chromium VI sulfide. Chromium III sulfate is Cr2(SO4)3
There is no "formula, just the symbol Cr(VI) or CrVI.
Annon:The chemical formula of chromium II sulfate is CrSO4.Miki-San-X: ActuallySince this is probably Ionic naming since it starts with a metal and ends with a non metal you would take chromium (II) Sulfate and cross them-Like so-Start:Cr(II) SO4 (-2)We know that sulfate is SO4 with a -2 superscript and that chromium is a transition metal, but that it has a positive charge to counteract the negative charge of the -2.You will drop the charge and cross them-Cr2(SO4)2since you brought the -2 from the sulfate down to the chromium it becomes positive 2 because you dropped the charge before crossing. The reason you put the (SO4) in parenthesis is because you cannot, in a problem like this, have 42 next to your polyatomic ion. You have TWO of that ion, NOT 42.Hope I helped
Chromium has four oxidation states: 2, 3, 4, and 6.Iodine has one, and it's -1.There will be a iodide for each oxidation state of chromium.CrI2 Chromium (II) iodideCrI3 Chromium (III) iodideCrI4 Chromium (IV) iodideCrI6 Chromium (VI) iodide
The formula for the compounds: Chromium (VI) Phosphate; Vanadium (IV) Carbonate; Tin (II) Nitrite?
Sulfur dioxide gas turns acidifiedpotassium dichromate(VI) solution from orange to green.Chromium is reducedfrom (VI) to (III). potassium sulfur sulfuric chromium(III) potassiumdichromate(VI) + dioxide + acid sulfate + sulfate + water.