2NaBr (aq) + Cl2 (g) --> 2NaCl (aq) + Br2 (g)
I believe that this is right :)
This is a single displacement reaction, also known as a single replacement reaction. In this reaction, chlorine (Cl2) displaces bromine (Br2) from potassium bromide (KBr) to form potassium chloride (KCl) and elemental bromine (Br2).
Aluminum bromide (AlBr3) + Chlorine (Cl2) → Aluminum chloride (AlCl3) + Bromine (Br2)
The balanced chemical equation for this reaction is 2NaBr + Cl2 -> 2NaCl + Br2. It shows that one molecule of molecular chlorine reacts with two molecules of sodium bromide to produce two molecules of sodium chloride and one molecule of bromine.
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
Chlorine reacts with aqueous potassium bromide to displace bromine due to its higher reactivity. This displacement reaction is known as a redox reaction because chlorine is being reduced while bromine is being oxidized. The resulting products are potassium chloride and bromine.
Chlorine + Magnesium Bromide ----> Magnesium Chloride + Bromine
Yes. Chlorine is more reactive than bromine.
This is a single displacement reaction, also known as a single replacement reaction. In this reaction, chlorine (Cl2) displaces bromine (Br2) from potassium bromide (KBr) to form potassium chloride (KCl) and elemental bromine (Br2).
Yes, chlorine will react with potassium bromide to form potassium chloride and bromine. This is a displacement reaction where the more reactive chlorine displaces bromine from potassium bromide.
Aluminum bromide (AlBr3) + Chlorine (Cl2) → Aluminum chloride (AlCl3) + Bromine (Br2)
The reaction between aqueous chlorine and sodium bromide solution results in the displacement of bromine by chlorine, forming sodium chloride and bromine gas as products. This is a redox reaction where chlorine is reduced and bromine is oxidized.
The balanced chemical equation for this reaction is 2NaBr + Cl2 -> 2NaCl + Br2. It shows that one molecule of molecular chlorine reacts with two molecules of sodium bromide to produce two molecules of sodium chloride and one molecule of bromine.
In the reaction between chlorine gas and bromide ions, the chlorine gas oxidizes the bromide ions to form bromine gas and chloride ions. This is a redox reaction where chlorine undergoes reduction by gaining electrons from bromide ions.
You would get Sodium Chloride and Bromine. This is because Chlorine is a more reactive group 7, (halogen), element that bromine, we know this because it is above bromine in the periodic table group, it is therefore more electronegative. When the reaction occurs, the Chlorine displaces the Bromine and the solution turns brown.
When chlorine gas reacts with potassium bromide, the chlorine will displace bromine in the compound forming potassium chloride and bromine gas. The color of the mixture will change from colorless to reddish-brown due to the formation of bromine gas.
Bromine does not react with aqueous potassium chloride because it is less reactive than chlorine. Chlorine is more electronegative than bromine and hence has a higher tendency to displace bromine from its compounds. Consequently, bromine remains unreactive in the presence of aqueous potassium chloride.
The reaction between aluminum bromide and chlorine gas forms aluminum chloride and bromine gas. This is a double displacement reaction where the bromine from aluminum bromide is replaced by chlorine to form new compounds. The balanced chemical equation for this reaction is 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2.