from the butay
The flame produced by burning butane is typically blue in color.
To determine the amount of butane that combusts, we need to use the enthalpy of combustion for butane, which is -2877 kJ/mol. Since the heat produced is 1550 kJ, we can set up a proportion to find the amount of butane consumed. By dividing the heat produced by the enthalpy of combustion per mole, we will get the number of moles of butane consumed. From there, you can convert moles to grams using the molar mass of butane (58.12 g/mol).
A blue flame is produced upon ignition of butane, indicating complete combustion with efficient energy release.
The equation is 2C4H10 + 13O2 --> 8CO2 + 10H2O This means that for each mole of butane there are 5 moles of water produced. We have 7.01 g of butane = 7.01/58 moles of butane = 0.12 moles. Thus we will get 5 x 0.12 moles of water, = 5 x 0.12 x 18 g of water = 10.88 g.
The balanced chemical equation for the combustion of butane is: 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O From the equation, 2 moles of butane produce 8 moles of carbon dioxide. So, 600 g of butane is approximately 7.23 moles. Therefore, the amount of carbon dioxide produced would be 29 moles, which is equivalent to 704 g.
The flame produced by burning butane is typically blue in color.
Butane is an alkane produced synthetically from petroleum.
To determine the amount of butane that combusts, we need to use the enthalpy of combustion for butane, which is -2877 kJ/mol. Since the heat produced is 1550 kJ, we can set up a proportion to find the amount of butane consumed. By dividing the heat produced by the enthalpy of combustion per mole, we will get the number of moles of butane consumed. From there, you can convert moles to grams using the molar mass of butane (58.12 g/mol).
A blue flame is produced upon ignition of butane, indicating complete combustion with efficient energy release.
The heat produced when 1 mole of butane is completely combusted is -2877 kJ. The molar mass of butane is 58.12 g/mol, so 4.6 g is 0.079 moles. Therefore, the heat produced when 4.6 g of butane is combusted is -227.1 kJ.
The equation is 2C4H10 + 13O2 --> 8CO2 + 10H2O This means that for each mole of butane there are 5 moles of water produced. We have 7.01 g of butane = 7.01/58 moles of butane = 0.12 moles. Thus we will get 5 x 0.12 moles of water, = 5 x 0.12 x 18 g of water = 10.88 g.
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
The balanced chemical equation for the combustion of butane is: 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O From the equation, 2 moles of butane produce 8 moles of carbon dioxide. So, 600 g of butane is approximately 7.23 moles. Therefore, the amount of carbon dioxide produced would be 29 moles, which is equivalent to 704 g.
The bright, vibrant red or pink flame in some butane torches is typically produced by introducing certain metal salts or compounds into the butane fuel mixture. These additives can create colorful flames by emitting specific wavelengths of light when they combust.
The time it takes to melt a metal with a butane lighter will vary depending on the type of metal and the intensity of the heat produced by the lighter. Generally, it would take a significant amount of time and may not be practical to melt metal with just a butane lighter.
C1 gases (methane) are typically produced through natural processes such as anaerobic decomposition of organic matter, while C4 gases (butane) are usually produced as byproducts of petroleum refining or natural gas processing. Methane can also be produced synthetically through various processes like steam reforming of natural gas, whereas butane is mainly a byproduct of oil refining operations.
Butane is a gas. Gases are not malleable.