answersLogoWhite

0

First let's calculate the formula mass of SiO2. It is 28.1 + 2(16.0) = 60.1. The amount of SiO2 can be calculated as 6.54/60.1 = 0.109mol. Now in one formula unit of SiO2 there is one Si atom. So, the amount of Si atoms present is 0.109mol. To get the numerical quantity, multiply it by the Avogadro's constant, and we get 0.109 × 6.02 × 10^23 = 6.55 x 10^22 atoms

User Avatar

Wiki User

10y ago

What else can I help you with?

Continue Learning about Chemistry
Related Questions

How many grams of sand are needed to make 45 grams of silicon?

To make silicon from sand, you would need to extract the silicon dioxide (SiO2) from the sand. The atomic mass of silicon dioxide is 60 grams/mole. Since the molar ratio of silicon to silicon dioxide is 1:1, you would need 45 grams of sand to obtain 15 grams of silicon (45 grams x 1 mol Si/60 g SiO2).


What is the density of silicon dioxide?

Silicon dioxide has a density of 2.63 g/cm3.


How many grams of oxygen are in 10.00x1028 molecules of silicon dioxide?

10.00 X 10^28 = 1.0 X 1^29 ( always use scientific notation in chemistry ) 1.0 X 10^29 molecules silicon dioxide (1 mole SiO2/6.022 X 10^23)(2 mole O/1 mole SiO2)(16.0 grams/ 1 mole O) = 5.3 X 10^6 grams of oxygen


How many atoms of silicon are contained in 8.5 x 10-5gm?

To calculate the number of silicon atoms in 8.5 x 10^-5 grams of silicon, you would first determine the molar mass of silicon (28.09 g/mol) and then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. In this case, there are approximately 1.29 x 10^16 atoms of silicon in 8.5 x 10^-5 grams.


How many grams of silicon would there be in a sample that contained 9.99 x 1025 atoms?

To determine the grams of silicon in the sample, you need to know the molar mass of silicon. Since silicon's atomic mass is approximately 28 g/mol, you can calculate the grams of silicon by dividing the number of atoms by Avogadro's number and then multiplying by silicon's molar mass. This calculation would provide you with the amount of silicon in grams in the given sample.


Why is silicon dioxide used in Pam baking spray?

40 grams


How many grams of silicon would there be in a sample that contained 9.991052 atoms?

1 mol of Si contains 6.02 x 1023 atoms (avogadro constant). Amount of Si = (9.99x1052) / (6.02x1023) = 3.75mol Molecular mass of Si is 28.1. Mass of Si = 3.75 x 28.1 = 105g


How many silicon atoms are there in 1.00 g of silicon?

Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon. The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 1 gram of silicon? In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atoms In 1 gram silicon = 1/28.0855 x 6.02214179 x 1023 = 2.144217404 x 1022 atoms


How many grams of silicon would there be in a sample that contained 9.99 x 1052 atoms?

To calculate the mass of silicon in the sample, you would first convert the number of atoms to moles using Avogadro's number. Then, you would calculate the mass of silicon in grams using the molar mass of silicon (28.0855 g/mol). The final mass would depend on the number of atoms in the sample.


How many grams do 3.61020 atoms of silicon weigh?

Each mole of particles have 6.02 x 10^23 particles. (3.6 x 10^20) / (6.02 x 10^23) = 0.000598 mol of Silicon Ar of Si (Silicon) = 28.1g/mol mass = number of moles x Ar mass = 0.000598 mol x 28.1g/mol = 0.0168g of silicon


How many atoms1 cm2 for silicon?

Since silicon has a density of 2.33 grams/cm3 and an atomic weight of 28.0855 g/mol, 1 cm2 of silicon would contain approximately 9.74 x 10^22 atoms. This calculation assumes the silicon is in a crystalline form with close packing of atoms.


How many Si atoms in 12.5 g sample of silicon?

Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon.The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 12.5 gram of silicon?In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atomsIn 12.5 gram silicon = 12.5/28.0855 x 6.02214179 x 1023 = 2.680271755 x 1023 atomsRead more: How_many_silicon_atoms_are_there_in_1.00_g_of_silicon


How many atoms are in 65.6 g silicon?

The molar mass of Silicon is 28.09g Therefore if you have 65.6g, you divide that mass by 28.09g. 65.6g/28.09g = 2.34 mols. For atoms, you multiply that number by 6.02 x 1023. So 2.34 x 6.02 x 1023 = 1.41 x 1024.


How many atoms are in one gram of sand?

The number of atoms in one gram of sand can vary depending on its composition, but if we consider typical quartz sand, which is primarily composed of silicon dioxide (SiO₂), it contains about 2.65 grams per cubic centimeter. One gram of quartz sand would contain approximately 0.037 moles of SiO₂. Since each molecule of SiO₂ consists of three atoms (one silicon and two oxygen atoms), one gram of sand contains roughly 6.02 x 10²³ atoms, or about 2.2 x 10²⁴ atoms.


How many hydrogen atoms are present in 3.65 grams of water?

3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.


How many moles are in 3.4x10-7 grams of silicon dioxide?

To find the number of moles, we need to convert the given mass in grams to moles. The molar mass of silicon dioxide (SiO2) is approximately 60 grams/mol. Number of moles = (3.4x10^-7 grams) / (60 grams/mol) = 5.7x10^-9 moles.


How many moles are present in 11g of silicon?

To find the number of moles in 11 grams of silicon, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of silicon is approximately 28.09 g/mol. Therefore, the number of moles in 11 grams of silicon is 11 g / 28.09 g/mol, which is approximately 0.39 moles.


How many moles are there in 5 grams of silicon dioxide?

To determine the number of moles in 5 grams of silicon dioxide (SiO2), you first need to calculate the molar mass of SiO2. The molar mass of SiO2 is 60.08 g/mol. Then, use the formula Moles = Mass / Molar mass to find that there are approximately 0.083 moles in 5 grams of SiO2.


How many moles in 28.1 grams of silicon?

To determine the number of moles in 28.1 grams of silicon, you need to divide the given mass by the molar mass of silicon. The molar mass of silicon is 28.0855 g/mol. So, 28.1 grams of silicon is equal to 1 mole.


How many atoms and molecules are present in 64 grams of sulphur?

12.044*10^23 atoms 1.5055*10^23 S8 molecules