First let's calculate the formula mass of SiO2. It is 28.1 + 2(16.0) = 60.1. The amount of SiO2 can be calculated as 6.54/60.1 = 0.109mol. Now in one formula unit of SiO2 there is one Si atom. So, the amount of Si atoms present is 0.109mol. To get the numerical quantity, multiply it by the Avogadro's constant, and we get 0.109 × 6.02 × 10^23 = 6.55 x 10^22 atoms
Silicon dioxide has a density of 2.63 g/cm3.
10.00 X 10^28 = 1.0 X 1^29 ( always use scientific notation in chemistry ) 1.0 X 10^29 molecules silicon dioxide (1 mole SiO2/6.022 X 10^23)(2 mole O/1 mole SiO2)(16.0 grams/ 1 mole O) = 5.3 X 10^6 grams of oxygen
To determine the grams of silicon in the sample, you need to know the molar mass of silicon. Since silicon's atomic mass is approximately 28 g/mol, you can calculate the grams of silicon by dividing the number of atoms by Avogadro's number and then multiplying by silicon's molar mass. This calculation would provide you with the amount of silicon in grams in the given sample.
To calculate the mass of silicon in the sample, you would first convert the number of atoms to moles using Avogadro's number. Then, you would calculate the mass of silicon in grams using the molar mass of silicon (28.0855 g/mol). The final mass would depend on the number of atoms in the sample.
Each mole of particles have 6.02 x 10^23 particles. (3.6 x 10^20) / (6.02 x 10^23) = 0.000598 mol of Silicon Ar of Si (Silicon) = 28.1g/mol mass = number of moles x Ar mass = 0.000598 mol x 28.1g/mol = 0.0168g of silicon
To make silicon from sand, you would need to extract the silicon dioxide (SiO2) from the sand. The atomic mass of silicon dioxide is 60 grams/mole. Since the molar ratio of silicon to silicon dioxide is 1:1, you would need 45 grams of sand to obtain 15 grams of silicon (45 grams x 1 mol Si/60 g SiO2).
Silicon dioxide has a density of 2.63 g/cm3.
10.00 X 10^28 = 1.0 X 1^29 ( always use scientific notation in chemistry ) 1.0 X 10^29 molecules silicon dioxide (1 mole SiO2/6.022 X 10^23)(2 mole O/1 mole SiO2)(16.0 grams/ 1 mole O) = 5.3 X 10^6 grams of oxygen
To calculate the number of silicon atoms in 8.5 x 10^-5 grams of silicon, you would first determine the molar mass of silicon (28.09 g/mol) and then use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. In this case, there are approximately 1.29 x 10^16 atoms of silicon in 8.5 x 10^-5 grams.
To determine the grams of silicon in the sample, you need to know the molar mass of silicon. Since silicon's atomic mass is approximately 28 g/mol, you can calculate the grams of silicon by dividing the number of atoms by Avogadro's number and then multiplying by silicon's molar mass. This calculation would provide you with the amount of silicon in grams in the given sample.
40 grams
1 mol of Si contains 6.02 x 1023 atoms (avogadro constant). Amount of Si = (9.99x1052) / (6.02x1023) = 3.75mol Molecular mass of Si is 28.1. Mass of Si = 3.75 x 28.1 = 105g
To calculate the mass of silicon in the sample, you would first convert the number of atoms to moles using Avogadro's number. Then, you would calculate the mass of silicon in grams using the molar mass of silicon (28.0855 g/mol). The final mass would depend on the number of atoms in the sample.
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon. The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 1 gram of silicon? In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atoms In 1 gram silicon = 1/28.0855 x 6.02214179 x 1023 = 2.144217404 x 1022 atoms
Each mole of particles have 6.02 x 10^23 particles. (3.6 x 10^20) / (6.02 x 10^23) = 0.000598 mol of Silicon Ar of Si (Silicon) = 28.1g/mol mass = number of moles x Ar mass = 0.000598 mol x 28.1g/mol = 0.0168g of silicon
Since silicon has a density of 2.33 grams/cm3 and an atomic weight of 28.0855 g/mol, 1 cm2 of silicon would contain approximately 9.74 x 10^22 atoms. This calculation assumes the silicon is in a crystalline form with close packing of atoms.
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon.The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 12.5 gram of silicon?In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atomsIn 12.5 gram silicon = 12.5/28.0855 x 6.02214179 x 1023 = 2.680271755 x 1023 atomsRead more: How_many_silicon_atoms_are_there_in_1.00_g_of_silicon