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CCl4 forms covalent bonds. It is composed of carbon and chlorine atoms which share electrons to form stable molecules. Ionic bonds form between atoms with significantly different electronegativities.
ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
CCl6 doesn't exist. CCl4 and and C2Cl6 do however.
The gram molecular mass of carbon tetrachloride is 12.011 + 4(35.453) or 153.823. Each mole contains Avogadro's Number of molecules. Therefore, the number of molecules in 200 grams is (200/153.823) X Avogadro's Number or 7.83 X 1023 molecules, to the justified number of significant digits.
1 mole CCl4 = 153.811g CCl4 = 6.022 x 1023 molecules CCl4 567g CCl4 x (6.022 x 1023 molecules CCl4)/153.811g CCl4 = 2.22 x 1024 molecules CCl4
Iodine dissolves readily in CCl4 due to the presence of London dispersion forces between the iodine molecules and the non-polar CCl4 molecules. These weak intermolecular forces allow for iodine molecules to be dispersed throughout the CCl4 solvent.
it will not dissolve NH3 in poler molecules
CCl4 forms covalent bonds. It is composed of carbon and chlorine atoms which share electrons to form stable molecules. Ionic bonds form between atoms with significantly different electronegativities.
When iodine solution is added to CCl4 (carbon tetrachloride), the iodine molecules dissolve in the CCl4 solvent because they are nonpolar molecules. This results in a solution with a distinct purple color due to the presence of iodine. However, there is no chemical reaction between the iodine and CCl4 in this case.
The molar mass of CCl4 is 153,82 g.153,82 ------------------------------------6,02214129.10ex.23 (Avogadro number)22,4 g-------------------------------------xx = 0,877.10ex.23 molecules
ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
CCl6 doesn't exist. CCl4 and and C2Cl6 do however.
The gram molecular mass of carbon tetrachloride is 12.011 + 4(35.453) or 153.823. Each mole contains Avogadro's Number of molecules. Therefore, the number of molecules in 200 grams is (200/153.823) X Avogadro's Number or 7.83 X 1023 molecules, to the justified number of significant digits.
HCl and CO2 are dipole molecules because they have a significant difference in electronegativity between the bonded atoms, creating a dipole moment. Cl2 and CCl4 are nonpolar molecules as they have either symmetrical distribution of charge (Cl2) or the vector sum of the dipole moments cancel out (CCl4).
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).