ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will
^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
When BR2 reacts with H2O, it undergoes oxidation to form HBr and HOBr. This reaction involves the transfer of electrons from BR2 to H2O, resulting in the formation of these products.
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).
No it wont because it is non-polar and hence cannot break the hydrogen bonds in water and get dissolved
No. CHCl3 (Chloroform) is insoluble in water. Chloroform when mixed with water, will form two liquid layers and Chloroform will form the bottom layer. This nature of chloroform is explored in several biological and chemical techniques such as DNA isolation, separation of phyotochemicals etc
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
Bromine (Br2) will be soluble in carbon tetrachloride (CCl4) because both are nonpolar. Sodium nitrate (NaNO3) will be soluble in water (H2O) due to its ionic nature and the ability to form hydrogen bonds with water molecules; it will not dissolve in a nonpolar solvent like CCl4. Hydrochloric acid (HCl) is soluble in water and will dissociate into ions, making it insoluble in a nonpolar solvent like CCl4.
No, CCl4 (carbon tetrachloride) is more dense than H2O (water). The density of H2O is 1 g/cm3, while the density of CCl4 is 1.59 g/cm3.
When BR2 reacts with H2O, it undergoes oxidation to form HBr and HOBr. This reaction involves the transfer of electrons from BR2 to H2O, resulting in the formation of these products.
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).
No it wont because it is non-polar and hence cannot break the hydrogen bonds in water and get dissolved
No. CHCl3 (Chloroform) is insoluble in water. Chloroform when mixed with water, will form two liquid layers and Chloroform will form the bottom layer. This nature of chloroform is explored in several biological and chemical techniques such as DNA isolation, separation of phyotochemicals etc
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
The compound with the highest melting point among HCl, HBr, H2O, and Br2 is H2O (water). Water has a high melting point due to its strong hydrogen bonding, which requires a significant amount of energy to break apart the bonds between water molecules.
The coefficient distribution F of I2 between H2O and CCl4 refers to the partitioning of I2 between the two solvents. It quantifies the relative solubility of I2 in each solvent and is determined experimentally using a partition coefficient measurement. The coefficient distribution F is calculated as the concentration of I2 in CCl4 divided by the concentration of I2 in H2O at equilibrium.
No, carbon tetrachloride (CCl4) and water (H2O) do not form a homogeneous mixture because they are immiscible in each other. Carbon tetrachloride is non-polar while water is polar, making them separate into two distinct layers.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
Yes, NaOH (sodium hydroxide) is highly soluble in water.