No it wont because it is non-polar and hence cannot break the hydrogen bonds in water and get dissolved
ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).
CCl4 is a non polar solvent and therefore dissole ionic compounds
No. CHCl3 (Chloroform) is insoluble in water. Chloroform when mixed with water, will form two liquid layers and Chloroform will form the bottom layer. This nature of chloroform is explored in several biological and chemical techniques such as DNA isolation, separation of phyotochemicals etc
question itself is wrong, chloroform is solute and ccl4 is solvent, solute should dissolve in solvent and solvent cannot dissolve in solute
No, CCl4 (carbon tetrachloride) is more dense than H2O (water). The density of H2O is 1 g/cm3, while the density of CCl4 is 1.59 g/cm3.
ccl4 will dissolve better in water because likes dissolves likes, H2O is non-polar an CCL4 is also non polar where as ch2cl2 is polar(different to water) there for it wont dissolve in water but CCL4 will^^This is not true: water is polar. Therefore, since CCl4 is non-polar, and CH2Cl2 is polar, and like dissolves like, CH2Cl2 is more soluble.
It has to do with intermolecular forces. H2O has an oxygen with two hydrogens coming off of it. This forms two hydrogen bonds, which are much stronger than the London Dispersion Forces in CCl4. (Since CCl4 is non-polar, there are no Dipole-Dipole forces).
CCl4 is a non polar solvent and therefore dissole ionic compounds
Bromine (Br2) will be soluble in carbon tetrachloride (CCl4) because both are nonpolar. Sodium nitrate (NaNO3) will be soluble in water (H2O) due to its ionic nature and the ability to form hydrogen bonds with water molecules; it will not dissolve in a nonpolar solvent like CCl4. Hydrochloric acid (HCl) is soluble in water and will dissociate into ions, making it insoluble in a nonpolar solvent like CCl4.
No because water only dissolves polar covalent bonds and CH4 is Nonpolar
No. CHCl3 (Chloroform) is insoluble in water. Chloroform when mixed with water, will form two liquid layers and Chloroform will form the bottom layer. This nature of chloroform is explored in several biological and chemical techniques such as DNA isolation, separation of phyotochemicals etc
Carbon disulfide (CS2) would be best dissolved by carbon tetrachloride (CCl4) due to its nonpolar nature similar to CS2, NH3 would dissolve in water (H2O) due to their ability to form hydrogen bonds, CH3OH would dissolve in water due to their similar polar nature and ability to form hydrogen bonds, C6H6 (benzene) would dissolve in HBr due to their ability to form temporary dipoles and induce dipole-dipole interactions.
question itself is wrong, chloroform is solute and ccl4 is solvent, solute should dissolve in solvent and solvent cannot dissolve in solute
it will not dissolve NH3 in poler molecules
The coefficient distribution F of I2 between H2O and CCl4 refers to the partitioning of I2 between the two solvents. It quantifies the relative solubility of I2 in each solvent and is determined experimentally using a partition coefficient measurement. The coefficient distribution F is calculated as the concentration of I2 in CCl4 divided by the concentration of I2 in H2O at equilibrium.
Inert solvent is a solvent that does not react with your reaction system. means, it does not interfere between your reactants . . .Inert solvent like CCL4 does not do anything to Bromine, e.g. Bromine water, which is red-brown in colour, when added to CCL4 , its colour remains same.