One mole of any molecule contains avogadro number of molecules.
and that is equal to 6.023 X 1023
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
There are 1.204 x 10^24 water molecules in two moles of water. This is because one mole of anything contains Avogadro's number of particles, which is 6.022 x 10^23. Thus, two moles of water would have twice that number of molecules.
0.943 moles H2O (6.022 X 1023/1 mole H2O) = 5.68 X 1023 molecules of water ========================
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
The value is 1,328.10e-3 moles.
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
There are 1.204 x 10^24 water molecules in two moles of water. This is because one mole of anything contains Avogadro's number of particles, which is 6.022 x 10^23. Thus, two moles of water would have twice that number of molecules.
0.943 moles H2O (6.022 X 1023/1 mole H2O) = 5.68 X 1023 molecules of water ========================
Because they are.
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
The value is 1,328.10e-3 moles.
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
6 grams water (1 mole H2O/18.016 grams)(6.022 X 10^23/1 mole H2O) = 2.0 X 10^23 molecules of water
There is one water molecule in H2O
Formula mass / Formula weight / Molecular mass / Molecular weight of H2O = (1*2) + 16 = 18g 1 mol of H2O = 18g H2O 1 mol of H2O = 6.023 * 10^23 molecules In 18g H2O there are 6.023 * 10^23 molecules. So, In 1g H2O there are (6.023 * 10^23) / 18 molecules = 3.346 * 10^22 molecules Therefore, In 7.3g H2O there are (3.346 * 10^22) * 7.3 molecules = 2.443 * 10^23 molecules Ans: 2.443 * 10^23 molecules
Assuming a density of 1.0 g/ml for water, then 10 ml H2O = 10 g10 g H2O x 1 mol/18 g = 0.5555 moles H2O0.5555 moles x 6.02x10^23 molecules/mole = 3.34x10^23 molecules of H2O in 10 ml