Sucrose is C12H22O11. This means that there's 12 atoms of carbon, 22 atoms of hydrogen, and 11 atoms of oxygen. The total amount of atoms in sucrose is then 45.
1 mole of sucrose cotains 12 multiply by 6.023 exponent 23 atoms.
There are 16 individual oxygen atoms contained in one mole of Li2C2O4.
In 2.00 moles of sucrose, there are approximately 1.21 x 10^24 atoms. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (2.00). Each mole of sucrose contains 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
Sucrose has a chemical formula of C12H22O11, so it contains 11 oxygen atoms per molecule. In 3.65 mol of sucrose, the number of molecules can be calculated using Avogadro's number, and then multiplied by the number of oxygen atoms per molecule to find the total number of oxygen atoms. Therefore, in 3.65 mol of sucrose, there are 2.45 x 10^24 oxygen atoms.
The formula with this disaccharide is, C12H22O11 17.1 grams C12H22O11 (1 mole C12H22O11/342.296 grams)(11 mole O/1 mole C12H22O11)(6.022 X 10^23/1 mole O) = 3.31 X 10^23 atoms of oxygen ------------------------------------------
about 1.4*10^25
1 mole of sucrose cotains 12 multiply by 6.023 exponent 23 atoms.
There are 16 individual oxygen atoms contained in one mole of Li2C2O4.
In 2.00 moles of sucrose, there are approximately 1.21 x 10^24 atoms. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (2.00). Each mole of sucrose contains 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms.
Sucrose has a chemical formula of C12H22O11, so it contains 11 oxygen atoms per molecule. In 3.65 mol of sucrose, the number of molecules can be calculated using Avogadro's number, and then multiplied by the number of oxygen atoms per molecule to find the total number of oxygen atoms. Therefore, in 3.65 mol of sucrose, there are 2.45 x 10^24 oxygen atoms.
The formula with this disaccharide is, C12H22O11 17.1 grams C12H22O11 (1 mole C12H22O11/342.296 grams)(11 mole O/1 mole C12H22O11)(6.022 X 10^23/1 mole O) = 3.31 X 10^23 atoms of oxygen ------------------------------------------
The total number of atoms contained in a 1,00 mole sample of helium is 6,022 140 857.10e23.
Table sugar has the chemical name and formula of sucrose (C12H22O11). For every one mole of sucrose, 12 moles of carbon are contained. In order to calculate moles you take 12 multiplied by Avogadro's number of 6.0221413 x 10^23. That would equal 7.2x10^24 atoms of carbon per molecule of sucrose.
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
1 M = 1 mole/liter. so 2 M sucrose would contain 2 moles of sucrose in 1 liter of solution.So to find the volume of solution with 1 mole sucrose:V = (1 mole) / ( 2 mole/liter) = 0.5 liter ; 0.5 liter * (1000 mL/liter) = 500 mL
No, 1 mole of hydrogen atoms does not equal 1 mole of helium atoms. One mole of any element contains Avogadro's number of atoms (6.022 x 10^23), so 1 mole of hydrogen atoms would have that many hydrogen atoms, while 1 mole of helium atoms would have that many helium atoms.
Assuming you are speaking of sucrose (there are a lot of different sugars), about 1.58338 x 10^22 atoms. The molecular weight of sucrose is 342.30 g/mol so 9 grams would be approximately 0.026293 moles. Since there are 6.022140857(74)×10^23 atoms per mole, that would correspond to about 1.58338 x 10^22 atoms