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There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
A phosphate ion (PO4) contains 4 oxygen atoms, 1 phosphorus atom, and a total of 3 phosphate atoms.
Copper phosphate (Cu3(PO4)2) consists of 5 elements: copper (Cu), phosphorus (P), and oxygen (O).
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
Because copper (II) cations have a charge of +2 and phosphate anions have a charge of -3, the formula of anhydrous* copper (II) phosphate is Cu3(PO4)2. This shows that each formula unit contains 2 atoms of phosphorus. Therefore, the atoms of phosphorus in 4.8 formula units is 4.8 x Avogadro's Number, or about 2.9 X 1024 atoms, to the justified number of significant digits. ____________________________________ The answer to the problem will be the same if hydrated copper (II) phosphate is assumed, because the water of hydration contains no phosphorus and the quantity is specified in moles or formula units, but the formula would be different.
Copper phosphate contain Cu, P and O.
A phosphate ion (PO4) contains 4 oxygen atoms, 1 phosphorus atom, and a total of 3 phosphate atoms.
Copper is an element. You can have a single atom or many atoms and it's still copper.
Copper phosphate (Cu3(PO4)2) consists of 5 elements: copper (Cu), phosphorus (P), and oxygen (O).
It has 4 oxygen atoms.
Copper phosphate is an ionic compound.
Lithium phosphate has the chemical formula Li3PO4, which means it contains 3 lithium atoms, 1 phosphorus atom, and 4 oxygen atoms. In total, there are 8 atoms in lithium phosphate.
There are three copper II ions (Cu2+) and two phosphate ions (PO43-).