How many atoms are present in 18g ofC6H12O6?

Answer 1

Glucose has a molar mass of 180. There are thus 0.1 moles present in 18 g. 1 mole contains 6.022 x 1023 molecules. 0.1 moles contains 6.022 x 1022 molecules and so glucose with 24 atoms per molecule contains 24 x 6.022 x 1022 = 1.44528 x 1024 atoms.

Answer 2

To calculate the number of atoms in 18g of C6H12O6, we need to first calculate the number of moles of C6H12O6. Once we know the number of moles, we can use Avogadro's number (6.022 x 10^23) to determine the number of atoms. THe calculation would be Number of moles = mass / molar mass, so for C6H12O6 (glucose) the molar mass is 180 g/mol, so 18g / 180 g/mol = 0.1 mol. Then the number of atoms = number of moles x Avogadro's number, so 0.1 mol x 6.022 x 10^23 = 6.022 x 10^22 atoms.