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3.14 g Cu = # atoms

Take the known mass of copper multiply it by Avogadro number and divided by the atomic weight.

Atomic weight of copper:

63.5 g

3.14 g Cu (6.02 × 1023 atoms) / (63.5 grams) = 2.98 × 1022 atoms of Copper

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Related Questions

How many Cu atoms are present in 85mol?

To calculate the number of Cu atoms in 85 mol, you need to use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. So, for 85 mol of Cu, the number of Cu atoms would be 85 mol x 6.022 x 10^23 atoms/mol = 5.12 x 10^25 Cu atoms.


How may atoms of oxygen are present in Cu(NO3)2?

Copper(II) nitrate has six oxygen atoms.


How many atoms in cu(OH)2?

There are 5 atoms in one molecule of Cu(OH)2, comprising one copper (Cu) atom, two oxygen (O) atoms, and two hydrogen (H) atoms.


How many atoms are in CuNO3 2?

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How many oxygen atoms are present in a 14.0 g sample of Cu(NO3)2?

14.0 g x 1 mole/187.56 g = 0.0746 moles0.0746 moles Cu(NO3)2 x 6 moles O/mole Cu(NO3)2 = 0.448 moles O atoms0.448 moles O atoms x 6.02x10^23 atoms/mole = 2.70x10^23 atoms of oxygen


How many moles of atoms are in 450000000000000000000000 atoms of Cu?

Divide that number of atoms by 6.02x10^23 atoms/mole


How many atoms are in each elemental sample 4.0mol Cu?

4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================


How many oxygen atoms are there in a molecule of copper nitrate?

The compound copper nitrate has Cu(NO3)2 for a chemical formula. In that formula, we see that there is an NO3 radical present, and that there are 3 atoms of oxygen in that radical (the sub 3 after the O). But there are 2 of those NO3 radicals (the sub 2 outside of the parens) present in this compound. That means that there are 3 x 2 oxygen atoms in a molecule of copper nitrate, or 6 atoms of oxygen in Cu(NO3)2.


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1 mol Cu Atoms (6.02x10^23 atoms)


How many moles of Cu are in the 148 times 10 to the power 25 atoms?

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How many atoms in CU (NO3)2?

1 w


How many atoms are in CU(NO3)2?

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