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MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following:
(.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ...
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How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
How many potassium atoms are present in .01456 grams of potassium?
.01456 g (6.02 x 1023 atoms) / (39.1 g) = 2.24 x 1020 atoms
In the reaction between magnesium and oxygen the mass of magnesium and oxygen was 2.5 grams how much magnesium oxide was formed?
340 grams
How many atoms are present in 5 grams of AuCl3?
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms
How many atoms are present in 6.81g of copper?
6.81 grams copper (1 mole Cu/63.55 grams)(6.022 X 1023/1 mole Cu) = 6.45 X 1022 atoms of copper ----------------------------------------
How many atoms are present in 7.92g of calcium fluoride?
7.92 grams calcium fluoride (1 mole CaF2/78.08 grams)(6.022 X 1023/1 mole CaF2) = 6.11 X 1022 atoms of calcium fluoride --------------------------------------------------
How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?
Theoretically the mass is 62,3018 g.
What is the number of magnesium atoms that equal a mass of 24.31?
24.31 grams of magnesium is one mole of magnesium, so that is 6.022 X 1023 atoms of magnesium.
What is the formula for magnesium and fluorine?
Magnesium (II) fluoride, MgF2 Formula weight: 62.302 grams/moleSee the Related Questions for how to calculated the molecular weight of any molecule!
How many grams of sodium contain the same numberof atom as 15grams of magnesium?
Let us find Magnesium atoms first. 15 grams magnesium (1 mole Mg/24.31 grams)(6.022 X 10^23/1 mole Mg) = 3.72 X 10^23 atoms magnesium Now take this an drive to grams sodium 3.72 X 10^23 atoms (1 mole Na/6.022 X 10^23)(22.99 grams/1 mole Na) = 14 grams of sodium ----------------------------
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
How many atoms in 36g of magnesium?
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.10.6 grams Mg / (24.3 grams) × (6.02 × 1023 atoms) = 2.63 × 1023 atoms
How much sodium hydroxide in grams must be added to seawater to completely precipitate 86.9mg of magnesium?
how much sodium hydroxide in grams must be added to seawater to precipitate 86.9mg of magnesium present?
How many oxygen atoms are present in 1.659 grams of ozone gas?
1.659 [grams] / 47.998 [grams / mol] * 6.02214179(30)×1023 [molecules / mole] * 3 [atoms / molecule]. A bunch.
How many hydrogen atoms are present in 3.65 grams of water?
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
There are 6 grams of magnesium and 4 grams of oxygen if 8 grams of magnesium oxide is produced?
2
How many grams is 0.348 mol of magnesium?
Molecular mass of magnesium = 24.305 g/mol. 0.478 g/24.305 g/mol = .0197 mols
