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MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following:
(.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ...
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How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
How many fluoride atoms are in a tube of toothpaste?
The number of fluoride atoms in a tube of toothpaste can vary depending on the brand and formulation. However, a standard 4 oz tube of toothpaste typically contains around 0.24 grams of fluoride, which is roughly equal to 1.7 x 10^19 fluoride atoms.
How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
How much fluorine in grams was formed when the mass ratio of sodium to fluorine in sodium fluoride is 1 to 21 to 1 A sample of sodium fluoride produced 27point7 grams of sodium upon decomposition?
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
How many grams in magnesium?
The atomic mass of magnesium (Mg) is approximately 24.305 grams per mole.
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
How many grams of magnesium fluoride would you produce if you added 24 grams of magnesium to 38 grams of fluorine?
Theoretically the mass is 62,3018 g.
How many atoms are present in 7.92g of calcium fluoride?
Calculate the number of moles of calcium fluoride by dividing the mass by its molar mass. The molar mass of calcium fluoride (CaF2) is 78.08 g/mol. Then, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of atoms present in 7.92g of calcium fluoride.
What is the formula for magnesium and fluorine?
Magnesium (II) fluoride, MgF2 Formula weight: 62.302 grams/moleSee the Related Questions for how to calculated the molecular weight of any molecule!
How many fluoride atoms are in a tube of toothpaste?
The number of fluoride atoms in a tube of toothpaste can vary depending on the brand and formulation. However, a standard 4 oz tube of toothpaste typically contains around 0.24 grams of fluoride, which is roughly equal to 1.7 x 10^19 fluoride atoms.
What is the number of magnesium atoms that equal a mass of 24.31?
24.31 grams of magnesium is one mole of magnesium, so that is 6.022 X 1023 atoms of magnesium.
How many grams of sodium contain the same numberof atom as 15grams of magnesium?
Let us find Magnesium atoms first. 15 grams magnesium (1 mole Mg/24.31 grams)(6.022 X 10^23/1 mole Mg) = 3.72 X 10^23 atoms magnesium Now take this an drive to grams sodium 3.72 X 10^23 atoms (1 mole Na/6.022 X 10^23)(22.99 grams/1 mole Na) = 14 grams of sodium ----------------------------
What number of atoms is present in 8 gm of magnesium?
In 8 mg Magnesium is:8(mg) / 24.31(mg/mmole) = 0.329 mmole Mg(molar mass Mg being 24.31 mg/mmole)In 0.329 mmole Mg is:0.329(mmole) * 6.02*1023(atoms/mole)*10-3(mole/mmole) == 1.98*1020 atoms of Mg.(Avogadro's Number being 6.02*1023)
How many atoms in 36g of magnesium?
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.10.6 grams Mg / (24.3 grams) × (6.02 × 1023 atoms) = 2.63 × 1023 atoms
How many grams of magnesium would be required to produce 4.00 grams of magnesium oxide?
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
How many hydrogen atoms are present in 3.65 grams of water?
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
There are 6 grams of magnesium and 4 grams of oxygen if 8 grams of magnesium oxide is produced?
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