1 Magnesium and 2 Fluoride
MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following: (.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ... Enjoy your free high school chemistry answer!
Yes, a covalent bond exists between the magnesium atom and the fluorine atoms in MgF2. Magnesium forms a +2 cation and each fluorine forms a -1 anion, resulting in a ionic compound with covalent character due to the sharing of electron density between the atoms.
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
The formula for magnesium fluoride is: MgF2 magnesium is a +2 charge, fluoride is a -1 so each fluoride gives 1 electron to satisfy its electron shell.
KClO3 ===========potassium chlorate The potassium, K +, is ionically bonded to the chlorate, a polyatomic ion, CLO3 -, but the chlorine and oxygen atoms are covalently bonded together.
The empirical formula of magnesium fluoride is MgF2. This is because the ratio of magnesium atoms to fluorine atoms in the compound is 1:2.
MgF2 has a molecular weight of 24+19*2 = 62g. Thus, 31 grams of MgF2 represent .5mol. There are 6.022*10^23 particles per mole. Since MgF2 has three atoms in it, we can find the number of atoms by the following: (.5 mol)(6.022*10^23 particles/mol)(3 atoms in MgF2) = ... Enjoy your free high school chemistry answer!
One: The formula for magnesium fluoride is MgF2. Since each mole of fluorine molecules, which have the formula F2, contains two moles of fluorine atoms, one mole of each is the right ratio.
Yes it will form ionic bond (as in NaF or MgF2) or covalent bond as in F2 or ClF3)
Yes, a covalent bond exists between the magnesium atom and the fluorine atoms in MgF2. Magnesium forms a +2 cation and each fluorine forms a -1 anion, resulting in a ionic compound with covalent character due to the sharing of electron density between the atoms.
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
Magnesium (II) fluoride, MgF2 Formula weight: 62.302 grams/moleSee the Related Questions for how to calculated the molecular weight of any molecule!
MgF2 is higher that LiF do to the greater bond strength in MgF2. This greater strength is indicated by the charge of Mg (+3) which is higher than the +2 charge of Li. Also the MgF2 is larger in mass.
MgF2
The formula for magnesium fluoride is: MgF2 magnesium is a +2 charge, fluoride is a -1 so each fluoride gives 1 electron to satisfy its electron shell.
There are two fluoride ions in magnesium fluoride (MgF2), as the formula indicates the ratio of magnesium ions (Mg2+) to fluoride ions (F-) is 1:2.
KClO3 ===========potassium chlorate The potassium, K +, is ionically bonded to the chlorate, a polyatomic ion, CLO3 -, but the chlorine and oxygen atoms are covalently bonded together.