The 2 in front means 2 formula units, or 2 moles of the compound Al3O2. So you would multiply the 2 in front times the subscripts in the formula unit Al3O2. In the formula unit Al3O2, there are 5 atoms. Multiply that by the 2 in front and you get 10 atoms.
Well Al2O3 has 2 atoms of aluminum (Al2) and 3 atoms of Oxygen (O3). Thus, as there are 2Al2O3 molecules there are 4 atoms of aluminum.
By looking at the formula Al2O3 you find that there are 3 oxygen atoms in each formula unit. 2Al2O3 is 2 formula units.
So you have six oxygen atoms
4 atoms of AL and 6 atoms of O for a total of 10 atoms
two atoms
4
5
6
Because the numbers of aluminum and oxygen atoms are not the same on both sides of the equation, so the equation is not balanced. In order to be balanced, the numbers of atoms of each element must be the same on both sides of the equation. The correct equation is 4Al + 3O2 --> 2Al2O3. This gives 4 aluminum atoms and 6 oxygen atoms on both sides of the equation, so it is balanced.
4Al + 3O2 -> 2Al2O3
There are 20 atoms and there are 6 Carbon atoms, 8 Hydrogen atoms, 6 Oxygen atoms.
A molecule is a combination of atoms. To know how many atoms are in one molecule, you have to find out what atoms are in the molecule.
4
6
Aluminium + Oxygen ----> Aluminium oxideBalanced equation:4 Al + 3 O2 ----> 2 Al2O3
This is a synthesis reaction, and when it's balanced, it looks like this: 4Al + 3O2 --> 2Al2O3
No. If you mean 4Al3O2. And If you mean 4Al + 3O2 ------> AL2O, it is still not balance.
It's Aluminum Oxide.
he following equation is balanced 4Al 3O2 -- 2Al2O3 is not a balanced equation.on the reactants side we haev 4 atoms of Al and we have 24 atoms of oxygen. but on products side we have 24Al but 6 atoms of oxygen.this violates conservation of mass.
4Al + 3O2 ---> 2Al2O3
Because the numbers of aluminum and oxygen atoms are not the same on both sides of the equation, so the equation is not balanced. In order to be balanced, the numbers of atoms of each element must be the same on both sides of the equation. The correct equation is 4Al + 3O2 --> 2Al2O3. This gives 4 aluminum atoms and 6 oxygen atoms on both sides of the equation, so it is balanced.
2Al2O3 --> 4Al + 3O2
The ionic compound Al2O2 forms when aluminum reacts with oxygen.
4Al + 3O2 -> 2Al2O3