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An angstrom = 1 X 10^-10 meters

1.0 mm = 0.001 meters

so,

1.9 * 1 X 10^-10 = 1.9 X 10^-10 meter per chromium

so

0.001 meters ( 1 meter/1.9 X 10^-10)

= 5263158 atoms of chromium

------------------------------------------

( 5.3 X 10^6 atoms )

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Q: How many chromium atoms would have to be lined up to span 1.0 mm if chromium is about 1.9 Å?
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