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The hybridization is sp3 because N is bonded to 3 hydrogen groups and contains two unpaired electrons. For these three bonds and unpaired electron the s orbital and three p orbitals hybridize forming __ __ __ __ sp3 hybridized orbitals.
There are 6 Chlorine has 7 valence electrons, and since 2 of them can occupy one s orbital, there needs to be 5 p orbitals for everything else. (5+1=6)
Multiply the orbitals in that sublevel by 2. The s sublevel has one orbital and can contain 2 electrons. The p sublevel has three orbitals and can contain 6 electrons. The d sublevel has five orbitals and can contain 10 electrons. The f sublevel has seven orbitals and can contain 14 electrons.
Yes, some molecular compounds such as nitrogen dioxide (NO2) contain unpaired electrons.
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6 degenerate orbitals allows for seven electrons, five of which are unpaired. ans is 6
The hybridization is sp3 because N is bonded to 3 hydrogen groups and contains two unpaired electrons. For these three bonds and unpaired electron the s orbital and three p orbitals hybridize forming __ __ __ __ sp3 hybridized orbitals.
There are 6 Chlorine has 7 valence electrons, and since 2 of them can occupy one s orbital, there needs to be 5 p orbitals for everything else. (5+1=6)
Magnetic objects must contain atoms with unpaired electrons. No unpaired electrons=no magnetism.
Multiply the orbitals in that sublevel by 2. The s sublevel has one orbital and can contain 2 electrons. The p sublevel has three orbitals and can contain 6 electrons. The d sublevel has five orbitals and can contain 10 electrons. The f sublevel has seven orbitals and can contain 14 electrons.
Yes, some molecular compounds such as nitrogen dioxide (NO2) contain unpaired electrons.
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Nitrogen molecule does not contain any unpaired electron in its molecular orbitals. Unpaired electron is needed to keep up the mechanism of burning.
Its the s and p orbitals
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The last orbitals are 'p' orbitals which contain 5 electrons.