In the ionic bond between sodium and chlorine in NaCl, one electron is transferred from the sodium atom to the chlorine atom. Sodium becomes positively charged and chlorine becomes negatively charged, forming the ionic bond.
In a combination reaction between sodium (Na) and chlorine, electrons are transferred from sodium to chlorine. This results in the formation of sodium ions (Na+) and chloride ions (Cl-), which then combine to form sodium chloride (NaCl) through ionic bonding.
One electron is transferred from sodium to chlorine in the ionic bond between sodium and chlorine in NaCl. Sodium loses one electron to achieve a stable electron configuration with a full outer shell, becoming a positively charged ion (Na+), while chlorine gains this electron to achieve a stable electron configuration, becoming a negatively charged ion (Cl-).
When an ionic bond forms between sodium and chlorine, the valence electron from the sodium atom is transferred to the chlorine atom. This transfer results in the formation of positively charged sodium ions and negatively charged chloride ions, which are then attracted to each other to create the ionic bond.
When sodium and chlorine combine to form sodium chloride (table salt), sodium donates an electron to chlorine. Sodium becomes a positively charged ion (Na+) while chlorine becomes a negatively charged ion (Cl-). This ionic bond forms due to the attraction between the oppositely charged ions.
The bond in the diatomic chlorine molecule Cl2 is a covalent bond where electrons are shared between atoms. In sodium chloride NaCl, the bond is an ionic bond where electrons are transferred from sodium to chlorine, resulting in the formation of positively and negatively charged ions that are attracted to each other.
Only one, from sodium to chlorine.
In a combination reaction between sodium (Na) and chlorine, electrons are transferred from sodium to chlorine. This results in the formation of sodium ions (Na+) and chloride ions (Cl-), which then combine to form sodium chloride (NaCl) through ionic bonding.
Only one electron is transferred.
One electron is transferred from each sodium to each chloride.
1
1
Only one, from sodium to chlorine.
The single valence electron of a neutral sodium atom is transferred to the valence shell of a neutral chlorine atom to form the stated bond; therefore, the answer is 1.
One electron is transferred from sodium to chlorine in the ionic bond between sodium and chlorine in NaCl. Sodium loses one electron to achieve a stable electron configuration with a full outer shell, becoming a positively charged ion (Na+), while chlorine gains this electron to achieve a stable electron configuration, becoming a negatively charged ion (Cl-).
When sodium bonds with chlorine to form table salt (sodium chloride), the sodium's valence electron is transferred to chlorine. This transfer results in sodium losing one electron to achieve a full outer shell of electrons (achieving a stable electron configuration), while chlorine gains one electron to also achieve a full outer shell. This transfer of electrons creates an ionic bond between the two atoms.
When an ionic bond forms between sodium and chlorine, the valence electron from the sodium atom is transferred to the chlorine atom. This transfer results in the formation of positively charged sodium ions and negatively charged chloride ions, which are then attracted to each other to create the ionic bond.
Each sodium will transfer 1 electron. So, for NaCl, one electron is transferred. In Na2SO4 (sodium sulfate), 2 electrons will be transferred (1 electron from each sodium).