Groups determine the number of electrons on the outer shell of an atom.
When elements react, they want to complete their outer most shell. Filling the outer most shell is called the octet rule.
In the cases of groups 1, 2 and 3, they want to donate, 1, 2 or 3 electrons to lose the outer most shell and form a completed outer shell.
It depends on the element. But ultimately, the number they lose is determined by how many will achieve a full outer shell. For example, sodium has one valence (outer shell) electron. It loses that one electron to have 8 valence electrons in the next shell.See related questions below.
The oxidation numbers in the first two groups tend to be positive because these elements have a tendency to lose electrons and form cations. Elements in Group 1 and Group 2 have 1 and 2 valence electrons, respectively, making it easier for them to lose these electrons and achieve a more stable electron configuration by forming ions with a positive charge.
Potassium will lose 1 electron to form a 1+ ion.
Electrons lose in case of potassium. It looses 1 electron.
Metals more readily lose electrons to form positive ions. This is because metals have a few valence electrons and a low ionization energy, making it easier for them to lose electrons and achieve a stable electron configuration.
It depends on the element. But ultimately, the number they lose is determined by how many will achieve a full outer shell. For example, sodium has one valence (outer shell) electron. It loses that one electron to have 8 valence electrons in the next shell.See related questions below.
The oxidation numbers in the first two groups tend to be positive because these elements have a tendency to lose electrons and form cations. Elements in Group 1 and Group 2 have 1 and 2 valence electrons, respectively, making it easier for them to lose these electrons and achieve a more stable electron configuration by forming ions with a positive charge.
Potassium will lose 1 electron to form a 1+ ion.
Electrons lose in case of potassium. It looses 1 electron.
The oxidation states of selenium are: 1 to 6 and -1, -2.
Metals more readily lose electrons to form positive ions. This is because metals have a few valence electrons and a low ionization energy, making it easier for them to lose electrons and achieve a stable electron configuration.
Valence electrons are the electrons present in the outermost shell of an atom.You can easily determine the number of valence electrons an atom can have by looking at its Group in the periodic table.For example, atoms in Groups 1 and 2 have 1 and 2 valence electrons, respectively.Atoms in Groups 13 and 18 have 3 and 8 valence electrons, respectively.
Their valance electrons form an octet. Each compound wants to have 8 valence electrons (which forms an octet). Groups 1 and 2 have 1 and 2 valence electrons respectively. 16 and 17 have 6 and 7 respectively. So together, they form 8.
System overload (explodes) (boom) (smoke) (etc.)
Transition metals typically lose 1 to 4 electrons to achieve a stable electron configuration. The number of electrons lost depends on the specific transition metal and its position in the periodic table.
group 1...is 1 valence. group 2...is 2 valence.
Group 1 elements a.k.a. Alkali metals lose 1 electron to form 1+ ions