It'll have to lose two to have a stable octet.
Magnesium would have to lose 2 electrons to have a complete octet on the outer shell and become stable.
This would be magnesium, based on the number of protons. Since the protons is equal to the number of electrons it is a neutral atom. Given the number of protons in the atom, the isotope would be magnesium-26.
A magnesium atom would need 6 electrons to complete its highest occupied electron shell. In practice, a magnesium atom almost never does this, because the energy required would be too great. Instead, the magnesium atom transfers 2 electrons to one or more atom that are more electronegative than magnesium and thereby forms a magnesium ion with an electrical charge of +2. In this ion, the highest occupied shell of a magnesium atom is completely empty of electrons.
An atom with 12 electrons, such as a neutral magnesium atom, will contain 2 electrons in its first energy level, 8 electrons in its second energy level, and 2 electrons in its third energy level. The electron configuration table for magnesium would look like this: 1s2 2s2 2p6 3s2 For the atom of magnesium to become "stable," it would have to lose those two valence electrons in its outermost shell by forming an ionic bond with another atom, thus becoming a magnesium ion with a -2 charge, written as Mg-2.
12; and that would be a magnesium atom.
Mg or magnesium has 2 electrons in its outer shell. O or oxygen is 2 electrons short of a full shell. The oxygen takes up the magnesium's spare electrons and gets a full outer shell and a charge of 2- (cos of the extra electrons). The magnesium gets a full outer shell cos it lost the spare 2 and gets a charge of 2+ (cos it lost 2 electrons that were balancing out the protons in the nucleus).So, one atom completely donates electrons to another atom. That's ionic bonding.
2
No. A atom is stable when it has a full valence shell. The way this works is (2,8,8,8...) For an example magnesium which has 12 electrons. Magnesium loses 2 electrons ( so it has 2, 8 and then has a full outer shell) to gain a full outer charge which results in a charge of 2+.
Losing 2 electrons gives it 10 - which is the same electron configuration as the noble (and extremely stable) gas Neon.
This would be magnesium, based on the number of protons. Since the protons is equal to the number of electrons it is a neutral atom. Given the number of protons in the atom, the isotope would be magnesium-26.
The magnesium has 2 valence electron while the oxygen misses 2 electron to complete its octet. An atom is always more stable when it has 8 valence electrons. The magnesium will create an ionic bond with the oxygen by giving its 2 electrons to form Magnesium Oxide, MgO.
Neutral atom of magnesium has 12 electrons.
A magnesium atom would need 6 electrons to complete its highest occupied electron shell. In practice, a magnesium atom almost never does this, because the energy required would be too great. Instead, the magnesium atom transfers 2 electrons to one or more atom that are more electronegative than magnesium and thereby forms a magnesium ion with an electrical charge of +2. In this ion, the highest occupied shell of a magnesium atom is completely empty of electrons.
An atom with 12 electrons, such as a neutral magnesium atom, will contain 2 electrons in its first energy level, 8 electrons in its second energy level, and 2 electrons in its third energy level. The electron configuration table for magnesium would look like this: 1s2 2s2 2p6 3s2 For the atom of magnesium to become "stable," it would have to lose those two valence electrons in its outermost shell by forming an ionic bond with another atom, thus becoming a magnesium ion with a -2 charge, written as Mg-2.
12; and that would be a magnesium atom.
It an atom has 12 electrons and is neutral, then it must be Mg (magnesium), and magnesium has 2 valence electrons which would be used in bonding.
A stable sodium atom has 11 electrons.
Loses two electrons.