What is al2o3???
If you mean Al2O3 , then there are two elements. viz. Aluminium(Al) and oxygen(O).
The numbers indicate that number of atoms of each element present. . There two aluminium atoms and three oxygen atoms in the molecule.
Chemically, it is aluminium oxide, commercially known as 'bauxite'.
NB
When writing chemical formula; for single letter symbols is always a CAPITAL letter. Hence oxygen is 'O' , not 'o'
Similarly, for a two letter symbol , the first letter is always a CAPITAL letter, and the second letter is always small/lower case. Hence aluminium is 'Al' , not 'al'.
This is the recognised international standard, and will be found on the Periodic Table.
Al2O3 is a compound. It is known as alumina and is a combination of the elements aluminum (Al) and oxygen (O).
Al and S combine to form aluminum sulfide, Al2S3
In the given reaction, the stoichiometry is 1:1 for Fe2O3 to Al2O3. So the number of moles of Al2O3 formed will be the same as the number of moles of Fe2O3 originally present.
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
There is no symbol for Al2O3 as it is a compound, chemical symbols are for elements
Al2O3 is a compound. It is known as alumina and is a combination of the elements aluminum (Al) and oxygen (O).
Al and S combine to form aluminum sulfide, Al2S3
To determine how many moles of aluminum (Al) are produced from 20 moles of aluminum oxide (Al2O3), we need to use the balanced chemical equation for the reduction of Al2O3. The equation is: 2 Al2O3 → 4 Al + 3 O2. From this, we see that 2 moles of Al2O3 produce 4 moles of Al. Therefore, from 20 moles of Al2O3, we can calculate that 20 moles of Al2O3 would produce 40 moles of Al.
Aluminum oxide, Al2O3, is an ionic compound. There are no molecules in it.
In the given reaction, the stoichiometry is 1:1 for Fe2O3 to Al2O3. So the number of moles of Al2O3 formed will be the same as the number of moles of Fe2O3 originally present.
A formula shows constituent elements and their ratios. In the formula Al2O3, you can see aluminum and oxygen bonded in a 2-3 ratio.
We know that Al2O3 is the chemical formula for aluminum oxide.
Al2O3 is aluminum oxide.
Al2O3 + 6HBr = 2Albr3 + 3H2O
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
please re-write that so we can understand