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so you find the ratio of Aluminum to Oxygenin this case it is 2:3
and then because the total mole is 2.16
for aluminum:
2.16/5*2 = 0.864
for oxygen:
2.16/5*3 = 1.296
hope this helped :D
Wiki User
∙ 11y ago
Wiki User
∙ 10y ago1 mole of Al2O3 has 2 moles of Al
2.16 moles Al2O3 will have 2x that number
4.32moles Al per 2.16 moles Al2O3
Anonymous
Wiki User
∙ 11y ago1 mole of Al2O3 has 2 moles of Al
2.16 moles Al2O3 will have 2x that number
4.32moles Al per 2.16 moles Al2O3
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Calculate the number of moles in 6.80g of Al2O3?
3.66x10^-3 g mol
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g
How do you calculate the mass of aluminum oxide produced when 3.75 moles of aluminum burn in oxygen?
Aluminum Oxide is Al2O3 and Al = 27 and oxygen =16 so the molar mass is 102 g/mol Al2O33.75 mol Al ~ 3.75/2 mol Al2O3 ~ (3.75/2)mol * 102 g/mol = 191.25 = 191 gram Al2O3
What is the percentage of aluminum in aluminum oxide (Al2O3)?
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3UNKNOWN: % Al3+EQUATION:% Al3+...=...g Al3+x 100...g Al2O3% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
What is the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced show how you got it?
4Fe + 3O2 -> 2Fe2O3 is the balanced equation.It'll need enough oxygen (> (0.46*3)/4 mole O2)to give (0.46*2)/4 mole Fe2O3, so 0.23 mole Fe2O3is produced.
What is the mass in grams of 9.27 moles of Al2O3?
The molar mass of Al2O3 is 101.96 g/mol. To calculate the mass of 9.27 moles of Al2O3, you would multiply the moles by the molar mass: 9.27 mol x 101.96 g/mol = 945.442 g. So, the mass of 9.27 moles of Al2O3 is approximately 945.442 grams.
Calculate the number of moles in 6.80g of Al2O3?
3.66x10^-3 g mol
What is the theoretical yield of aluminum oxide if 2.40 mole of aluminum metal is exposed to 2.10 mol of oxygen?
Balanced equation: 4Al(s) + 3O2(g) ==> 2Al2O3(s)2.40 mol Al ==> 1.2 moles Al2O3 (mole ratio of Al2O3 : Al is 2:4 or 1:2)2.10 mol O2 ==> 1.4 moles Al2O3 (mole ratio of Al2O3:O2 is 2:3)Therefore, Al is the limiting reactant.Theoretical yield will thus be 1.2 moles Al2O3. If you need mass, it is 1.2 moles x 102 g/mol = 122 g
What is the theoretical yield of aluminum oxide if 2.60 mol of aluminum metal is exposed to 2.25 mol of oxygen?
the answer is 4.7 1] Figure out how many moles of Al and O2 2.5g is. 2] Compare the ratio of the moles from A to the 2:3 ratio in Al2O3; do you have more Al proportionately than O2 or vice versa ? This is called 'finding which reagent is limiting".... 3] Take whichever reagent was limiting and find out how many moles of Al2O3 you can get from it. THen find the mass.
How do you calculate the mass of aluminum oxide produced when 3.75 moles of aluminum burn in oxygen?
Aluminum Oxide is Al2O3 and Al = 27 and oxygen =16 so the molar mass is 102 g/mol Al2O33.75 mol Al ~ 3.75/2 mol Al2O3 ~ (3.75/2)mol * 102 g/mol = 191.25 = 191 gram Al2O3
How many grams of alcl3 are produced from with 8.0 moles of al2o3. 6cl2 plus 2al2o3 equals 3o2 plus 4alcl3 equals?
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
What is the percentage of aluminum in aluminum oxide (Al2O3)?
The formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.GIVEN: mass of Al3+ = 53.964 g Al3+;Molar mass of Al2O3 = 581.77 g Al2O3UNKNOWN: % Al3+EQUATION:% Al3+...=...g Al3+x 100...g Al2O3% Al3+...=...53.964g Al3+x100......=...9.2758% Al3+581.77g Al2O3
How many moles of aluminum are needed to react completely with 1.8 mole of FeO?
24 mols of aluminum must have reacted since aluminum oxide is Al2O3
What is the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced show how you got it?
4Fe + 3O2 -> 2Fe2O3 is the balanced equation.It'll need enough oxygen (> (0.46*3)/4 mole O2)to give (0.46*2)/4 mole Fe2O3, so 0.23 mole Fe2O3is produced.
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
How many moles of CO2 are produced when 2.1 mol of C2H2 react?
How many mol of H are in 4.51 mol H2O?
4,51 moles hydrogen exist.
How many moles of NaCl are in 737 g of NaCl?
mol = mass/Mr mol = 737/ 58.44 moles of NaCl = 12.61
