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Al2O3 is a compound. It is known as alumina and is a combination of the elements aluminum (Al) and oxygen (O).
Al and S combine to form aluminum sulfide, Al2S3
In the given reaction, the stoichiometry is 1:1 for Fe2O3 to Al2O3. So the number of moles of Al2O3 formed will be the same as the number of moles of Fe2O3 originally present.
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
so you find the ratio of Aluminum to Oxygenin this case it is 2:3and then because the total mole is 2.16for aluminum:2.16/5*2 = 0.864for oxygen:2.16/5*3 = 1.296hope this helped :D
There is no symbol for Al2O3 as it is a compound, chemical symbols are for elements
Al2O3 is a compound. It is known as alumina and is a combination of the elements aluminum (Al) and oxygen (O).
Al and S combine to form aluminum sulfide, Al2S3
Aluminum oxide, Al2O3, is an ionic compound. There are no molecules in it.
In the given reaction, the stoichiometry is 1:1 for Fe2O3 to Al2O3. So the number of moles of Al2O3 formed will be the same as the number of moles of Fe2O3 originally present.
A formula shows constituent elements and their ratios. In the formula Al2O3, you can see aluminum and oxygen bonded in a 2-3 ratio.
We know that Al2O3 is the chemical formula for aluminum oxide.
Al2O3 is aluminum oxide.
Al2O3 + 6HBr = 2Albr3 + 3H2O
Fe2O3 + 2Al ===> Al2O3 + 2FeIn this reaction the number of moles of Al2O3 produced is dependent on the number of moles of Fe2O3 and Al that one starts with. For every 1 mole Fe2O3 and 2 moles Al, one gets 1 moles of Al2O3.
please re-write that so we can understand
To find the number of moles, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Divide the given mass (49.3 g) by the molar mass to get the number of moles of Al2O3 present. 49.3 g / 101.96 g/mol ≈ 0.483 moles of Al2O3.