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Mass of 1 mole of AL2(SO4)3 =340g

By unitary method, we get 340g=1 mole

12g= 12/340 moles

1 mole contains 6.022*1023 atoms

12/340 moles contain 12/340*6.022*1023 atoms=21.25*1021 atoms.

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14y ago
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9y ago

" al(po4)3 " as stated in this question is probably a misspelled formula for aluminum phosphate AlPO4.

Otherwise aluminum dihydrogen phosphate Al3(H2PO4) could possibly be meant by the questioner.

Please rephrase this question.

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Q: How many grams in 12.96 moles of al(po4)3?
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