Density of H2 in liquid is 0.07099 g/L
so 31.6 ml = 0.0316 Liters
0.07099 g/L = mass in grams/0.0316 Liters
= 2.24 X 10^-3 grams
To calculate the number of molecules, you first need to determine the number of moles of H2 in the 21.25 gram sample using the molar mass of H2 (2 grams/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
1 mole H2 = 2.016g H2 = 6.022 x 1023 molecules H210g H2 x 1mol H2/2.016g H2 x 6.022 x 1023 molecules H2/1mol H2 = 3 x 1024 molecules H2 (rounded to 1 significant figure)
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
To calculate the number of molecules, you first need to determine the number of moles of H2 in the 21.25 gram sample using the molar mass of H2 (2 grams/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
The answer is 20,664 g ammonia.
To find the grams of H2 needed, we first calculate the moles of NH3 using its molar mass. Then, we use the balanced chemical equation to determine the mole ratio of H2 to NH3. Finally, we convert moles of H2 to grams using its molar mass.
None. There is no hydrogen in sodium
Mass (g) = Mr * Moles If you rearrange it, you get Moles = Mass/Mr Working with a 2dp periodic table you get: Moles = 2/1.01 =1.98 There are 1.98 moles of hydrogen in 2g of H2 gas.
The molecular weight of H2, which is a diatomic molecule of hydrogen, is approximately 2.01588 grams per mole.
cuo
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
1 mole H2 = 2.016g H2 = 6.022 x 1023 molecules H210g H2 x 1mol H2/2.016g H2 x 6.022 x 1023 molecules H2/1mol H2 = 3 x 1024 molecules H2 (rounded to 1 significant figure)
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
11 g hydrogen are needed.
89,6 g ammonia are obtained.