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How many grams of calcium carbonate are required to prepare 50.0 g of calcium oxide?
10
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How many grams are in 2.8 moles of calcium carbonate?
2,8 moles of calcium carbonate have 240,208 g.
How many ions of carbonate present in 40 grams of calcium carbonate?
There are 6 ions of carbonate present in 40 grams of calcium carbonate. This is because each molecule of calcium carbonate (CaCO3) contains one carbonate ion (CO3^2-) alongside one calcium ion (Ca^2+), giving a total of 2 ions per one molecule of calcium carbonate.
What is the difference between the masses of sodium bicarbonate and calcium carbonate?
The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.
How many moles are there in 200 grams of Calcium Carbonate?
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
How much calcium carbonate in grams can be dissolved by 5.00 grams of hydrochloric acid?
The molar mass of calcium carbonate is 100.09 g/mol and the molar mass of hydrochloric acid is 36.46 g/mol. Using the mole ratio of the balanced chemical equation, you can calculate the amount of calcium carbonate that can be dissolved by 5.00 grams of hydrochloric acid, which is approximately 12.43 grams.
How many grams are in 2.8 moles of calcium carbonate?
2,8 moles of calcium carbonate have 240,208 g.
How many grams of calcium oxide will remain after 12.25grams of calcium carbonate is completely decomposed?
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
How many ions of carbonate present in 40 grams of calcium carbonate?
There are 6 ions of carbonate present in 40 grams of calcium carbonate. This is because each molecule of calcium carbonate (CaCO3) contains one carbonate ion (CO3^2-) alongside one calcium ion (Ca^2+), giving a total of 2 ions per one molecule of calcium carbonate.
What is the difference between the masses of sodium bicarbonate and calcium carbonate?
The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.
How many grams of calcium in 418 grams of Ca CO 3?
There are 40.08 grams of calcium in 100 grams of CaCO3. To find the amount of calcium in 418 grams of CaCO3, you can set up a proportion and calculate that there are approximately 167.2 grams of calcium in 418 grams of CaCO3.
How many moles are there in 200 grams of Calcium Carbonate?
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
How much calcium carbonate in grams can be dissolved by 5.00 grams of hydrochloric acid?
The molar mass of calcium carbonate is 100.09 g/mol and the molar mass of hydrochloric acid is 36.46 g/mol. Using the mole ratio of the balanced chemical equation, you can calculate the amount of calcium carbonate that can be dissolved by 5.00 grams of hydrochloric acid, which is approximately 12.43 grams.
If a balanced equation of calcium chloride dihydrate and sodium carbonate with the calcium chloride dihydrate is 1.0g what would the weighed measurement be of sodium carbonate?
0.720940834 grams
How many ions of calcium present in 40 grams of calcium carbonate?
In calcium carbonate, the molar mass is 100.1 g/mol. The molar mass of calcium is 40.08 g/mol. Therefore, the percentage of calcium in calcium carbonate is 40.08/100.1 * 100 = 40%. Thus, in 40 grams of calcium carbonate, there are 40% of calcium, which is equivalent to 40/40.08 = 0.997 moles of calcium. Since calcium forms 1+ ions, there are 0.997 * 6.022 * 10^23 = 6.02 * 10^23 ions of calcium present.
How many grams are in 1.25 moles of calcium carbonate?
To answer this we must first find the molar mass of calcium carbonate. CaCO3Ca= 40.08gC=12.01gO= 16.00g (we have three oxygens so 16.00x3 is 48.00g)40.08+12.01+48.00= 100.09 gNow that we have the molar mass we can find how many grams there are:1.25 moles CaCo3 x (100.09 g CaCO3/ 1 mole CaCO3)= 125.11 grams CaCO3Therefore we'd have about 125 grams of CaCO3
How many moles of calcium carbonate are in 1.719 grams?
Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.
What is the mass of 0.5 moles of calcium carbonate?
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.
