This question sound like one that can easily be answered if one has a general chemistry textbook. My advice is to look at doing some unit conversions to find out how many moles of propane are in 36.1 g of propane first. With a balanced chemical equation for combustion, and assuming the propane is the limiting reagent, use dimensional analysis to convert your moles of propane to moles of carbon dioxide.
The reaction for the complete combustion of propane is:
C3H8 + 5O2 --> 3CO2 + 4H2O
So for every mole of propane combusted 3 moles of carbon dioxide are formed. Therefore combusting 10 moles of propane will form 30 moles of carbon dioxide.
C3H8 + 5O2 -> 3CO2 + 4H2O
30 moles propane gas (3 mole CO2/1 mole C3H8)(1 mole C/1` mole CO2)
= 90 moles of carbon produced
-----------------------------------------( could have been different id carbon and carbon dioxide were not one to one as an internal molecule )
The complete combustion of propane occurs according to the following balanced equation: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that three moles of carbon dioxide are produced for each mole of propane burned. Therefore, burning 7.5 moles of propane will produce 22.5 moles of carbon dioxide. The gram molecular mass of carbon dioxide is 44.01; therefore, 22.5 moles has a mass of 22.5 x 44.01 or 9.9 X 102 grams, to the justified number of significant digits.
This is a chemical calculation. 57.9 MOLES of CO2 will formed.
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
smoke is produced when the propane burns because the carbon oxidises into carbon dioxide which forms smoke.
carbon dioxide and water oxygen gas and carbon atoms
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
The formula for the combustion of propane is: C2H6 + 5O2 --> 2CO2 + 3H2O So each mole of propane creates two moles of carbon dioxide. One mole of propane is 30 g, one mole of carbon dioxide is 44 g So each gram of propane creates (2x44)/30)= 2.93 g of carbon dioxide on combustion. In common terms a 20lb tank of p for a BBQ creates a bit less than 60 lb of carbon dioxide
If 15 liters of propane are completely consumed 90,25 grams of carbon dioxide are produced.
smoke is produced when the propane burns because the carbon oxidises into carbon dioxide which forms smoke.
9 particles
Burning propane is called combustion, in which propane combines with oxygen to form carbon dioxide and water.
carbon dioxide and water oxygen gas and carbon atoms
Many organic chemicals when combusted in oxygen can create Carbon dioxide and water
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
The volume of CO2 is 4,94 L.
30 moles
when you burn propane to complete combustion you will get a mixture of carbon dioxide and water vapor.
Any burning of wood, charcoal, coal, gas, propane or butane produced carbon dioxide/ These are the common BBQ fuels, so yes BBQs produce carbon dioxide. Even electrical BBQs get their power from fossil fuelled power plants and have a carbon dioxide impact.
The formula for the combustion of propane is: C2H6 + 5O2 --> 2CO2 + 3H2O So each mole of propane creates two moles of carbon dioxide. One mole of propane is 30 g, one mole of carbon dioxide is 44 g So each gram of propane creates (2x44)/30)= 2.93 g of carbon dioxide on combustion. In common terms a 20lb tank of p for a BBQ creates a bit less than 60 lb of carbon dioxide