1/2 liter of carbon dioxide
CH4 + 2O2 → CO2 + 2H2O + Energy (Heat) Methane + Oxygen → Carbon Dioxide + Water and Energy (Heat)
Oxygen + organic molecule -------> carbon dioxide + water
In a balanced combustion reaction of methane (CH₄), one molecule of methane reacts with two molecules of oxygen (O₂) to produce one molecule of carbon dioxide (CO₂) and two molecules of water (H₂O). Therefore, for every methane molecule burned, one carbon dioxide molecule is produced. The balanced equation is: CH₄ + 2 O₂ → CO₂ + 2 H₂O.
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
When methane burns in the presence of insufficient oxygen, incomplete combustion occurs, leading to the formation of carbon monoxide instead of carbon dioxide. Carbon monoxide is produced due to the partial oxidation of methane in limited oxygen supply. This reaction is less favorable as it produces a toxic gas, unlike complete combustion which forms carbon dioxide.
The answer is 24,15 g.
Burning 2 700 g of methane produce 70406 g of carbon dioxide.
The word for complete combustion of methane is carbon dioxide and water.
When carbon is burnt, Carbon Dioxide only is produced. When methane is burnt, both carbon dioxide and water are produced.
For the complete combustion of methane (CH4), the balanced chemical equation is: CH4 + 2O2 -> CO2 + 2H2O This equation shows that for every mole of methane that reacts, 2 moles of water (H2O) are produced.
To determine the moles of carbon dioxide produced from the combustion of methane, we first need to balance the chemical equation for the combustion of methane: CH4 + 2O2 → CO2 + 2H2O. From the balanced equation, we see that 1 mole of methane produces 1 mole of carbon dioxide. The molar mass of methane (CH4) is 16.05 g/mol, and the molar mass of carbon dioxide (CO2) is 44.01 g/mol. Therefore, 100.0 grams of methane is equivalent to 100.0 g / 16.05 g/mol = 6.23 moles of methane, which would produce 6.23 moles of carbon dioxide.
When methane is burned in oxygen, assuming complete combustion, the products are carbon dioxide and water.
CH4 + 2O2 → CO2 + 2H2O + Energy (Heat) Methane + Oxygen → Carbon Dioxide + Water and Energy (Heat)
A non luminous flame is produced when the air valve is opened enough to allow complete combustion of the methane gas.
When an organic molecule such as methane or ethanol undergoes complete combustion (in the presence of oxygen) it produces Carbon dioxide and water.
A non luminous flame is produced when the air valve is opened enough to allow complete combustion of the methane gas.
The general equation for the complete combustion of a hydrocarbon fuel such as fossil fuels is: hydrocarbon + oxygen → carbon dioxide + water For example, the complete combustion of methane (CH4) would be: CH4 + 2O2 → CO2 + 2H2O.