To calculate this, you would need to consider the molar masses of copper(II) sulfate pentahydrate and anhydrous copper(II) sulfate. Copper(II) sulfate pentahydrate has a molar mass that includes water molecules, so you need to determine the molar mass difference between the two compounds. Using this information, you can calculate the amount of copper(II) sulfate pentahydrate needed to obtain 10.0 grams of anhydrous copper(II) sulfate.
When water is added to anhydrous copper sulfate, it forms copper (II) sulfate pentahydrate, a blue crystalline solid. So, the color change observed is from white (anhydrous) to blue (pentahydrate) when water is added.
When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
The gram formula unit mass of copper (II) sulfate pentahydrate is 249.68. The gram formula unit mass of water is 18.015. Therefore, the mass of water of crystallization present in 50.0 g of copper (II) sulfate pentahydrate is: 50[5(18.015)/249.68] or 18.0 g, to the justified number of significant digits. (Note that the prefix penta- means five)
When copper sulfate pentahydrate is heated, the water molecules are driven off, leaving anhydrous copper sulfate as the solid residue. The chemical equation for this reaction is: CuSO4*5H2O(s) → CuSO4(s) + 5H2O(g).
When water is added to anhydrous copper sulfate, it forms copper (II) sulfate pentahydrate, a blue crystalline solid. So, the color change observed is from white (anhydrous) to blue (pentahydrate) when water is added.
When copper sulfate pentahydrate is heated, it undergoes a dehydration reaction where the water molecules are released, leaving behind anhydrous copper sulfate. This process is reversible, and when anhydrous copper sulfate is exposed to moisture, it will reabsorb water and form copper sulfate pentahydrate again.
When copper II sulfate pentahydrate is heated, it decomposes to form anhydrous copper II sulfate. The appearance of the resulting liquid is a clear, colorless solution. It does not have a specific odor.
Heating copper sulfate pentahydrate leads to a dehydration reaction, where water molecules are removed from the compound. This results in the formation of anhydrous copper sulfate.
The blue copper sulfate pentahydrate loss by heating water and become an anhydrous white sulfate.
Anhydrous cupric sulfate would form hydrated copper(II) sulfate when water is added to it. This process is exothermic and the anhydrous crystals would dissolve as the water molecules bond with the copper sulfate molecules to form a hydrated crystal structure.
Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate. When you heat copper sulfate pentahydrate it turns white as the water which is driven off by the heat. The white solid remaining is anhydrous copper sulfate. If you add water to the anhydrous copper sulfate an exothermic reaction occurs, you can feel the test-tube getting hot, as the blue copper sulfate pentahydrate is re-formed.
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
The balanced equation for the heating of copper(II) sulfate pentahydrate (CuSO4•5H2O) is: CuSO4•5H2O(s) -> CuSO4(s) + 5H2O(g). This reaction decomposes the pentahydrate compound into anhydrous copper(II) sulfate and water vapor.
The anhydrous copper(II) sulfate is white, the pentahydrate is blue.Iron is gray.
When heated, copper II sulfate pentahydrate decomposes to form anhydrous copper II sulfate and water vapor. The water molecules bound in the crystal structure are released as steam, leaving behind a white residue of anhydrous copper II sulfate powder.
The gram formula unit mass of copper (II) sulfate pentahydrate is 249.68. The gram formula unit mass of water is 18.015. Therefore, the mass of water of crystallization present in 50.0 g of copper (II) sulfate pentahydrate is: 50[5(18.015)/249.68] or 18.0 g, to the justified number of significant digits. (Note that the prefix penta- means five)