The substance turns white then grey and finally brown. That is because heat is given off and water evaporates.
cuso4 - 5h2o= cuso4 + 5h20 + heat
Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate. When you heat copper sulfate pentahydrate it turns white as the water which is driven off by the heat. The white solid remaining is anhydrous copper sulfate. If you add water to the anhydrous copper sulfate an exothermic reaction occurs, you can feel the test-tube getting hot, as the blue copper sulfate pentahydrate is re-formed.
penta = 5 copper(II) sulphate pentahydrate = CuSO4*5 H2O CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
It becomes a non-crystalline, powdery anhydrous salt.The hydrated (pentahydrate) form is chalcanthite, a bright blue crystal. The rare anhydrous ore form is called chalcocyanite, a gray or pale-green powdery rock.(If heated to 650 °C, copper sulfate becomes copper oxide and sulfur trioxide.)
Copper sulfate in its solid crystal from present as pentahydrate (CuSO4 5 H2O). When heated strongly it loses water molecules and becomes CuSO4. Note that CuSO4 5 H2O is blue in color whereas CuSO4 is colourless since absorption region shifted from visible region. On further heating it is dissociated to CuO.
The chemical decomposition is:CuSO4------ CuO + SO3
cuso4 - 5h2o= cuso4 + 5h20 + heat
Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate. When you heat copper sulfate pentahydrate it turns white as the water which is driven off by the heat. The white solid remaining is anhydrous copper sulfate. If you add water to the anhydrous copper sulfate an exothermic reaction occurs, you can feel the test-tube getting hot, as the blue copper sulfate pentahydrate is re-formed.
penta = 5 copper(II) sulphate pentahydrate = CuSO4*5 H2O CuSO4*5 H2O + heat --> CuSO4 + 5 H2O
The 5 water molecules are driven off by heating and the central Copper atom is no longer complexed by the water molecules which affects the energy and hence the color of the resulting anhydrous Copper Sulfate.
It becomes a non-crystalline, powdery anhydrous salt.The hydrated (pentahydrate) form is chalcanthite, a bright blue crystal. The rare anhydrous ore form is called chalcocyanite, a gray or pale-green powdery rock.(If heated to 650 °C, copper sulfate becomes copper oxide and sulfur trioxide.)
When copper sulfate is heated the observation is that it turns white as the water which is driven off by the heat. It is also stated that the white solid will remain and if water is added to the anhydrous copper sulfate a reaction will occur.
The gram formula unit mass of copper (II) sulfate pentahydrate is 249.68. The gram formula unit mass of water is 18.015. Therefore, the mass of water of crystallization present in 50.0 g of copper (II) sulfate pentahydrate is: 50[5(18.015)/249.68] or 18.0 g, to the justified number of significant digits. (Note that the prefix penta- means five)
It becomes a non-crystalline, powdery anhydrous salt.The hydrated (pentahydrate) form is chalcanthite, a bright blue crystal. The rare anhydrous ore form is called chalcocyanite, a gray or pale-green powdery rock.(If heated to 650 °C, copper sulfate becomes copper oxide and sulfur trioxide.)
It would form a white substance called anhydrous copper(II) Sulfate. *Anhydrous - Salts that do not contain water. Copper (II) sulfate pentahydrate is also called "blue vitriol," because it's, well, blue (vitriol is an old term for sulfuric acid). However, anhydrous copper (II) sulfate is white.
Copper sulfate in its solid crystal from present as pentahydrate (CuSO4 5 H2O). When heated strongly it loses water molecules and becomes CuSO4. Note that CuSO4 5 H2O is blue in color whereas CuSO4 is colourless since absorption region shifted from visible region. On further heating it is dissociated to CuO.
Copper sulfate is formed.