How many grams of fluorine are needed to react with 6.20 g of phosphorus?

Answer 1

Find number of moles of phosphorus

molar mass of phosphorus is 30.97g/mol

divide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/mol

n= m/M = 62.0g/123.88g/mol= 0.50 moles

Theoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.

So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.

So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.

Answer 2

It depends on the balanced chemical equation for the reaction between fluorine and phosphorus. If we assume it’s P + 5F2 → PF5, then you would need 31.0 grams of fluorine to react with the 6.20 grams of phosphorus. This is because the molar ratio of F to P is 5:1.