Find number of moles of phosphorus
molar mass of phosphorus is 30.97g/mol
divide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/mol
n= m/M = 62.0g/123.88g/mol= 0.50 moles
Theoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.
So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.
So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.
2.85
16.0 g
How many grams of oxygen are needed to react completely with 200.0 g of ammonia, NH3?4NH3(g) + 5O2(g) => 4NO(g) + 6H2O(g)
FRb
2Fe + 3F2 - 2FeF3 Iron + Fluorine - Iron Fluoride
An explosion
Find number of moles of phosphorusmolar mass of phosphorus is 30.97g/moldivide mass by molar mass to get the moles of phosphorus please that your molar mass mast be multiplied by 4 because you have four phosphorus atoms. 30.97*4= 123.88 g/moln= m/M = 62.0g/123.88g/mol= 0.50 molesTheoretically, there are 6 times the number of moles in fluorine than there are in phosphorus because of the ratio 1:6 but fluorine is diatomic gas so we multiply the number of moles by 12 instead of 6. 6 from the ratio times from fluorine being diatomic gas.So 0.5*12=6 moles of fluorine. we multiply that by the molar mass of fluorine multiplied by 12 because we 12fluorine atoms.So, 6= m/228g/mol so to find mass of fluorine we multiply moles times molar mass it gives us 1368g.
One
Curium is a sufficiently reactive metal; curium can react with oxygen, hydrogen, chlorine, iodine, fluorine, carbon, phosphorus, nitrogen antimony, arsenic etc.
16.0 g
47.6 grams
Aluminum does react with fluorine gas (which is the most corrosive substance known to science).
63 g of water are needed.
0,257 g hydrogen are needed.
cannot answer without more info.
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Berkelium can react with oxygen, sulfur, selenium, tellurium, carbon, nitrogen, hydrogen, chlorine, fluorine, bromine, phosphorus and very probable also with other elements.