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What is the formula for gallium III carbonate and gallium III oxide?
gallium (III) carbonate - Ga2(CO3)3 gallium (III) oxide - Ga2O3
If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
How many grams of calcium carbonate are required to prepare 50.0 g of calcium oxide?
This is a mass stoichiometry problem. Start with the balanced equation: CaCO3 --> CaO + CO2. Do a conversion from 50g CaO to moles: 56g/1mol=50g/x, x=.9 moles. The equation is balanced as written, with all coefficients understood to be 1. So: .9 moles CaO means .9 moles CaCO3. Do another conversion from moles to grams: 100g/1mol=x/.9 moles. Solve for x to get 90 grams. (56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)
How many grams of aluminum oxide can be formed by the reaction of 1020g of aluminum with oxygen?
To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
What is the formula for gallium III carbonate and gallium III oxide?
gallium (III) carbonate - Ga2(CO3)3 gallium (III) oxide - Ga2O3
What mass of calcium oxide is produced by heating 25 moles of calcium carbonate?
The molar ratio between calcium carbonate and calcium oxide is 1:1. So, 25 moles of calcium carbonate will produce 25 moles of calcium oxide. The molar mass of calcium oxide is 56.08 g/mol, so the mass of calcium oxide produced will be 25 moles * 56.08 g/mol = 1402 g.
How many moles are in 28 grams of calcium oxide?
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
If 5 grams of oxygen combines with 37.2 grams of uranium to form uranium oxide how many grams of the oxide are formed?
To find the grams of uranium oxide formed, we need to determine the molar mass of uranium and oxygen, calculate the moles of each element present, and finally the moles of uranium oxide formed. Then, we convert moles to grams using the molar mass of uranium oxide. The final answer for the grams of uranium oxide formed depends on the stoichiometry of the reaction.
How many moles are in 45 grams of potassium oxide?
45/94.2 is 0.4777 moles
How many moles of water ( dihydrogen oxide) are present in 75 grams?
75 grams water is equal to 4,166 moles.
How many grams of calcium oxide will remain after 12.25grams of calcium carbonate is completely decomposed?
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
Sodium will react with oxygen to form sodium oxide. Use the formula below to determine how many grams of sodium oxide will be formed if 46 grams of sodium are used in the reaction.?
62 grams a+
How many grams of calcium carbonate are required to prepare 50.0 g of calcium oxide?
This is a mass stoichiometry problem. Start with the balanced equation: CaCO3 --> CaO + CO2. Do a conversion from 50g CaO to moles: 56g/1mol=50g/x, x=.9 moles. The equation is balanced as written, with all coefficients understood to be 1. So: .9 moles CaO means .9 moles CaCO3. Do another conversion from moles to grams: 100g/1mol=x/.9 moles. Solve for x to get 90 grams. (56g=molar mass of calcium oxide; 100g=molar mass of calcium carbonate.)
What are the moles of lead II oxide formed when 463.4 grams lead II nitrate is heated on heat?
1,4 moles of lead(II) oxide are formed.
What is the chemical formula of Gallium carbonate?
Ionic gallium takes a 3+ (Ga3+) charge, and the hydroxide ion takes a 1- (OH-) charge. Therefore, the chemical formula (the combination of the ions to form an ionic compound) is Ga(OH)3, which satisfies all the charges. There are several other forms of ionic gallium compounds as well, include Gallium Oxide (Ga2O3) and Gallium Oxide Hydroxide (GaOOH).
How many grams of aluminum oxide can be formed by the reaction of 1020g of aluminum with oxygen?
To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.
