How many grams of iron oxide would be formed if 2 moles of iron completely react with oxygen gas?

Answer 1

The mass is 80 g iron)III) oxide.

Answer 2

One. because Iron (II) Oxide -----> FeO. so that's 1 iron for ever oxygen. So yeah just one. Unless your asking how many molecules? That would mean it's 6.02x10^23 since that's avagadro's number multiplied by the number of moles, which in this case is just 1.

Answer 3

Assuming "rust" to be Fe2O3 rather than a lesser predictable mix of various compounds... 2 moles Fe per 1 mole rust = 2.4/2 = 1.2mols rust. 3 moles O per 1 mole rust = 1.2 x 3 = 3.6 mols O. However...it may be noted that oxygen naturally exists as a diatomic molecule and so it should be explicitly stated whether the amount of monatomic or diatomic oxygen is wanted. 3.6 mols O ...or... 1.8 mols O2

Answer 4

Depend on it's valence state. Iron is transition metal and had many possible valence state (e.g. Fe2+ or Fe3+). For the case Fe2+ then it is just FeO and 1 atom informula but if it is Fe3+ then it is Fe2O3 and thus 2 atoms. You must check what written clearly, for iron oxide such as rust, it is wrtten as iron(III)oxide to stand for being a Fe3+.

Answer 5

The balanced chemical equation for the reaction between iron and oxygen to form iron oxide is: 4Fe + 3O2 -> 2Fe2O3

From the equation, 4 moles of iron react with 3 moles of oxygen to form 2 moles of iron oxide. Therefore, if 2 moles of iron react, half of the moles of iron oxide (1 mole) would be formed. To find the mass of iron oxide formed, you need to know the molar mass of Fe2O3, then multiply the moles of Fe2O3 by its molar mass to get the grams of iron oxide formed.

Answer 6

iron(II) oxide is FeO and has two ions Fe2+ and O2-

Answer 7

1.8 mol