How many grams of iron oxide would be formed if 2 moles of iron completely react with oxygen gas?

Answer 1

The mass is 80 g iron)III) oxide.

Answer 2

One. because Iron (II) Oxide -----> FeO. so that's 1 iron for ever oxygen. So yeah just one. Unless your asking how many molecules? That would mean it's 6.02x10^23 since that's avagadro's number multiplied by the number of moles, which in this case is just 1.

Answer 3

Assuming "rust" to be Fe2O3 rather than a lesser predictable mix of various compounds... 2 moles Fe per 1 mole rust = 2.4/2 = 1.2mols rust. 3 moles O per 1 mole rust = 1.2 x 3 = 3.6 mols O. However...it may be noted that oxygen naturally exists as a diatomic molecule and so it should be explicitly stated whether the amount of monatomic or diatomic oxygen is wanted. 3.6 mols O ...or... 1.8 mols O2

Answer 4

Depend on it's valence state. Iron is transition metal and had many possible valence state (e.g. Fe2+ or Fe3+). For the case Fe2+ then it is just FeO and 1 atom informula but if it is Fe3+ then it is Fe2O3 and thus 2 atoms. You must check what written clearly, for iron oxide such as rust, it is wrtten as iron(III)oxide to stand for being a Fe3+.

Answer 5

iron(II) oxide is FeO and has two ions Fe2+ and O2-

Answer 6

1.8 mol