You need to find a graph of solubility in your textbook. It should have temperature on the x-axis and "grams dissolved per 100 grams H2O" on the y-axis (or some such.)
Sodium nitrate is less soluble in cool water than warm. Use the graph to determine how many grams are dissolved at 50°C, multiplying by 2 since there are 200 grams H2O. Then determine how many grams are dissolved at 20°C, again multiplying by 2. Subtract the two numbers to find the grams that will precipitate
If the solution is saturated at 100°C and then cooled to 60°C, some of the potassium chloride will precipitate out of the solution. The exact amount that will precipitate depends on the solubility of potassium chloride at those temperatures. You would need to consult a solubility table or experimentally determine the solubility at those temperatures to calculate the amount of precipitate formed.
The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.
The amount of Epsom salt in a saturated solution depends on factors such as temperature and pressure. At room temperature, approximately 115 grams of Epsom salt can dissolve in 100 mL of water to form a saturated solution.
This is a solution of 10 g KCl/100 g water.
The solution is saturated at 20°C since 88g of sodium nitrate can dissolve in 100g of water. If you add an additional 10g of sodium nitrate, it will exceed the solubility limit at 20°C, causing the excess sodium nitrate to form a precipitate at the bottom of the solution.
If the solution is saturated at 100°C and then cooled to 60°C, some of the potassium chloride will precipitate out of the solution. The exact amount that will precipitate depends on the solubility of potassium chloride at those temperatures. You would need to consult a solubility table or experimentally determine the solubility at those temperatures to calculate the amount of precipitate formed.
The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.
The amount of Epsom salt in a saturated solution depends on factors such as temperature and pressure. At room temperature, approximately 115 grams of Epsom salt can dissolve in 100 mL of water to form a saturated solution.
The solution become saturated ove 124,6 g potassium nitrate.
To determine how many grams of potassium nitrate (KNO3) will settle out when cooling a saturated solution from 70°C to 50°C, you would need the solubility data for KNO3 at both temperatures. Typically, KNO3 is more soluble at higher temperatures, so as the solution cools, some KNO3 will precipitate out. If, for example, the solubility at 70°C is around 120 g/100 g water and at 50°C it's about 85 g/100 g water, then approximately 35 grams of KNO3 would settle out upon cooling. However, you would need the exact solubility values for an accurate calculation.
This is a solution of 10 g KCl/100 g water.
The solution is saturated at 20°C since 88g of sodium nitrate can dissolve in 100g of water. If you add an additional 10g of sodium nitrate, it will exceed the solubility limit at 20°C, causing the excess sodium nitrate to form a precipitate at the bottom of the solution.
The solubility of NH4Cl in water at 50°C is approximately 74 grams per 100 grams of water. To make a saturated solution, you would need to dissolve 148 grams of NH4Cl in 200 grams of water.
The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.
The percent by weight of NaCl in a saturated solution at 50 degrees Celsius is approximately 26.3%. This means that in every 100 grams of the solution, 26.3 grams is NaCl.
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
Approximately 18.4 grams of baking soda is required to make 50 ml of a saturated solution at room temperature.