The heat combustion of pentane involves reacting pentane with oxygen to produce carbon dioxide and water, releasing heat energy in the process. The chemical equation for the combustion of pentane is: C5H12 + 8O2 -> 5CO2 + 6H2O + heat.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
You can create a layered mixture by adding water to the mixture of pentane and chloroform. Since chloroform and pentane are miscible, adding water will create two separate layers due to their immiscibility with water. The less dense pentane-chloroform layer will float on top of the denser water layer.
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
The product of the reaction of pentane reacting with oxygen is carbon dioxide and water. This is due to the combustion of pentane in the presence of oxygen, which produces carbon dioxide and water as the final products.
A lot
Burning pentane, C5H12, is a combustion reaction in which pentane and oxygen will react to form carbon dioxide and water. The chemical equation is C5H12 + 8O2 --> 5CO2 + 6H2O
The heat combustion of pentane involves reacting pentane with oxygen to produce carbon dioxide and water, releasing heat energy in the process. The chemical equation for the combustion of pentane is: C5H12 + 8O2 -> 5CO2 + 6H2O + heat.
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
You can create a layered mixture by adding water to the mixture of pentane and chloroform. Since chloroform and pentane are miscible, adding water will create two separate layers due to their immiscibility with water. The less dense pentane-chloroform layer will float on top of the denser water layer.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
Yes, pentane can react with bromine water. In the presence of UV light, pentane can undergo a substitution reaction with bromine water where one or more hydrogen atoms are replaced by bromine atoms. This reaction can occur slowly at room temperature but is accelerated with the presence of UV light.
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
Pentane reacts with the oxygen in an excess of air to form five molecules of carbon dioxide and six molecules of water from each molecule of pentane; substantial heat is released by the reaction.
The product of the reaction of pentane reacting with oxygen is carbon dioxide and water. This is due to the combustion of pentane in the presence of oxygen, which produces carbon dioxide and water as the final products.
Water.
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.