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- Start with a balanced equation: C5H12 + 8O2 --> 5CO2 + 6H2O
- Find the number of moles of water in 72 g: FW of H2O is 18 g/mol so 72g/18g/mol is 4 mol
- Recall from the balanced equation the number of moles of water produced for each mole of Pentane: 6 waters for each pentane
- You produce 4 moles of water so the ratio from the balanced equation says you will need 4/6 mole of pentane
- Find the FW of the pentane: It (coincidentally) comes 72 grams/mol
- So, 0.67 mol of pentane times 72 g/mol will give the final answer of 48.24 grams
What else can I help you with?
What is heat combustion of pentane?
The heat combustion of pentane involves reacting pentane with oxygen to produce carbon dioxide and water, releasing heat energy in the process. The chemical equation for the combustion of pentane is: C5H12 + 8O2 -> 5CO2 + 6H2O + heat.
How many grams of hydrogen are needed to produce 30.0 grams of water?
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
How could you make a layered mixture of pentane chloroform and water if chloroform and pentane are miscible?
You can create a layered mixture by adding water to the mixture of pentane and chloroform. Since chloroform and pentane are miscible, adding water will create two separate layers due to their immiscibility with water. The less dense pentane-chloroform layer will float on top of the denser water layer.
How many moles of H2O are needed in order to produce 1 mole of glucose?
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
What is the product of the reaction of pentane reacting with oxygen?
The product of the reaction of pentane reacting with oxygen is carbon dioxide and water. This is due to the combustion of pentane in the presence of oxygen, which produces carbon dioxide and water as the final products.
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
What is produced when you burn pentane?
Burning pentane, C5H12, is a combustion reaction in which pentane and oxygen will react to form carbon dioxide and water. The chemical equation is C5H12 + 8O2 --> 5CO2 + 6H2O
What is heat combustion of pentane?
The heat combustion of pentane involves reacting pentane with oxygen to produce carbon dioxide and water, releasing heat energy in the process. The chemical equation for the combustion of pentane is: C5H12 + 8O2 -> 5CO2 + 6H2O + heat.
How many grams of hydrogen are needed to produce 30.0 grams of water?
The synthesis reaction is 2 H2 + O2 = 2 H2O. Every two moles of hydrogen reacts with one mole of oxygen to make two moles of water. Then 30.0 grams of water is 1.67 moles, and 1.67 moles of H2 has a mass of 3.37 grams. 25.0 grams of O2 is .781 moles, so 1.562 moles of H2 are needed, or 3.15 grams.
How could you make a layered mixture of pentane chloroform and water if chloroform and pentane are miscible?
You can create a layered mixture by adding water to the mixture of pentane and chloroform. Since chloroform and pentane are miscible, adding water will create two separate layers due to their immiscibility with water. The less dense pentane-chloroform layer will float on top of the denser water layer.
How many grams of hydrogen must be added to 800 grams of oxygen to produce 900 grams of water?
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
Does pentane react with bromine water?
Yes, pentane can react with bromine water. In the presence of UV light, pentane can undergo a substitution reaction with bromine water where one or more hydrogen atoms are replaced by bromine atoms. This reaction can occur slowly at room temperature but is accelerated with the presence of UV light.
How many moles of H2O are needed in order to produce 1 mole of glucose?
You need to dissolve 180 grams of glucose in water and make it up to 1000ml. this produces 1 M Glucose solution.
Word equation for combustion of pentane in plenty of air?
Pentane reacts with the oxygen in an excess of air to form five molecules of carbon dioxide and six molecules of water from each molecule of pentane; substantial heat is released by the reaction.
What is the product of the reaction of pentane reacting with oxygen?
The product of the reaction of pentane reacting with oxygen is carbon dioxide and water. This is due to the combustion of pentane in the presence of oxygen, which produces carbon dioxide and water as the final products.
What is needed to produce hydroelectric energy?
Water.
How many grams of water are produced when 2.5 mil oxygen reacts with hydrogen?
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
