The answer is 2,09 g water.
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
(CuSO4·xH2O) I would suggest heating in a crucible to a constant mass. A simple gravametric calculation using the balanced equation and m=n.gfm will give you a value for x x should be 5
To find the concentration of arsenic in ppb, we need to convert micrograms to grams and then calculate the concentration. First, convert 6.000 micrograms to grams by dividing by 1,000,000. This gives you 0.000006 grams of arsenic. Then, calculate the concentration by dividing the mass of arsenic by the volume of water (in liters) and multiplying by 1 billion to convert to ppb. The concentration of arsenic in the tap water sample is 24 ppb.
To get a sample of soluble salt, you can dissolve the salt in water, filter out any impurities, then evaporate the water to leave behind the salt crystals. This will give you a pure sample of the soluble salt.
When the temperature of a sample of water is -5 degrees Celsius, the water is frozen and in a solid state.
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
In order to determine the mass of the water sample, you would need to know the density of water. The density of water is approximately 1 g/cm3. Therefore, the mass of a 20 cm3 sample of water would be 20 grams (20 cm3 * 1 g/cm3 = 20 grams).
Fill a beaker with water, and weigh it. Weigh a sample of the mineral. That's the mass of the mineral. Put the sample in the beaker and weigh that. The weight of the water-filled beaker plus the weight of the mineral sample will be greater than the weight of the beaker with mineral sample and water. The difference is the weight of the displaced water, in grams. The volume of the mineral sample, in cubic centimeters is equal to the weight of the displaced water, in grams. Calculate the specific gravity of the mineral by dividing the weight of the mineral sample by the volume of the mineral sample. Example: your beaker weighs 40 grams. Filled with water, it's 1040 grams. The sample of mineral weighs 160 grams. The beaker with the sample of mineral and water weighs 1179.7 grams. The mineral, and the beaker with water would have a combined weight of 1200 grams, but the beaker with mineral and water weighs 20.3 grams less than that, so the mineral sample is displacing 20.3 cubic centimeters of water. Given a mass of 160 grams and a volume of 2.03 CC, the specific gravity would be found by dividing 160 by 20.3. It's 7.85. (Which happens to be the specific gravity of some iron.)
1 gm/ml
The energy released when 6 grams of water is condensed from water vapor is equal to the heat of vaporization of water. This is approximately 2260 joules per gram. So, for 6 grams of water, the total energy released would be around 13,560 joules.
The density of water is 1 gram per millilitre. That means this sample of water is 720 grams. Converting that to pounds, that is 1.587 pounds.
(CuSO4·xH2O) I would suggest heating in a crucible to a constant mass. A simple gravametric calculation using the balanced equation and m=n.gfm will give you a value for x x should be 5
Density is independent of the amount of material in a sample. A sample of a homogeneous substance used to find the density can have any volume. If a cm3 of the substance weighs 8.1 grams, then 10 cm3 will weigh 81.0 grams.We might consider water in a glass or bottle as an example. A small sample will have a given weight (mass) because water has a given density. Ten times that sample volume will have ten times the mass of that volume of water. The density of water does not change if we examine water in a small glass and another sample of the same water in a gallon jug.
The density of water at standard temperature and pressure is 1 gram/milliliter. The size of the sample is irrelevant. If the sample is pure, then one drop of it has the same density as a tankerful of it has.
According to Castro & Huber's Marine Biology textbook, there is about 1.3 g of magnesium in 1000g of ocean water.
The sample described is a saturated solution because it contains the maximum amount of NaCl that can dissolve in 1.0 liter of water at that temperature.
To calculate the energy released when 150 grams of water freezes, you need to know the heat of fusion of water, which is 334 J/g. You can then multiply this value by the mass of water to find the energy released. In this case, it would be 150 grams * 334 J/g = 50,100 J or 50.1 kJ.