Following the formula CxH2x-2 where X is the number of carbons in the desired Alkyne, you should get C8H14 (i think.....)
The alkyne - apex
Octyne contains 8 carbon atoms and a triple bond between two of those carbon atoms. It has the formula of C8H14. The triple bond can be in one of several locations, so there are several isomers.
An alkane with 20 carbons will have 42 hydrogens. This can be calculated using the formula 2n+2, where n is the number of carbons (C) in the alkane. So for an alkane with 20 carbons, the number of hydrogens would be 2(20) + 2 = 42.
In an alkane, each carbon atom is bonded to 4 hydrogen atoms. So, the number of hydrogens in an alkane can be determined by the formula 2n+2, where n is the number of carbon atoms in the alkane.
The number of hydrogens equals 2x the number of carbon atoms, plus 2 extra hydrogens.
The alkyne - apex
Octyne contains 8 carbon atoms and a triple bond between two of those carbon atoms. It has the formula of C8H14. The triple bond can be in one of several locations, so there are several isomers.
Four. A terminal carbon in an alkane is bonded to 3 hydrogens and 1 carbon, while a middle carbon is bonded to 2 hydrogens and 2 carbons.
2H2
An alkane with 20 carbons will have 42 hydrogens. This can be calculated using the formula 2n+2, where n is the number of carbons (C) in the alkane. So for an alkane with 20 carbons, the number of hydrogens would be 2(20) + 2 = 42.
In an alkane, each carbon atom is bonded to 4 hydrogen atoms. So, the number of hydrogens in an alkane can be determined by the formula 2n+2, where n is the number of carbon atoms in the alkane.
It is 1/2.
2 Hydrogens and 1 oxygen.
Water molecules are H2O so there are 2 Hydrogens bonded to 1 oxygen.
The number of hydrogens equals 2x the number of carbon atoms, plus 2 extra hydrogens.
Ethanol has 2 carbons, one oxygen, and 6 hydrogens.
H2O, water.