An alkane with n carbon atoms has 2n + 2 hydrogen atoms.
So, 42.
In an alkane, each carbon atom is bonded to 4 hydrogen atoms. So, the number of hydrogens in an alkane can be determined by the formula 2n+2, where n is the number of carbon atoms in the alkane.
Following the formula CxH2x-2 where X is the number of carbons in the desired Alkyne, you should get C8H14 (i think.....)
In an alkane the number of hydrogen atoms is two greater than twice the number of carbon atoms. If we reverse this rule, we find that the number of carbon atoms is one less than half the number of hydrogen atoms. 32/2=16 16-1=15 So our alkane would have 15 carbon atoms. This alkane would be pentadecane or one of its isomers.
there are 8 hydrogen atoms present in propane. There is 8 hydrogen atoms in propane, Each carbon has a valency of 4, 4 bonds with other atoms. Hydrogen has valency of 1. the general formula for alkanes is CnH2n +2 (n means number of that atom.) so to find how many hydrogens there with, say, 50 carbons you would do CnH2n + 2= C50H102. :)
Oxaloacetic acid is C4H4O5 and has four carbons
Four. A terminal carbon in an alkane is bonded to 3 hydrogens and 1 carbon, while a middle carbon is bonded to 2 hydrogens and 2 carbons.
In an alkane, each carbon atom is bonded to 4 hydrogen atoms. So, the number of hydrogens in an alkane can be determined by the formula 2n+2, where n is the number of carbon atoms in the alkane.
Answer: Molecules do not necessarily have any hydrogen atoms (e.g. NaCl has only sodium and chlorine and no hydrogen)The lowest number of hydrogens possibly present is one. This occurs in compounds like hydrogen chloride (HCl).Many molecules have two hydrogens, the simplest is hydrogen gas (H2)After this it's open season on hydrogens. Complex hydrocarbons (for example, polyethylene and heavy alkane oils) can have several hundred carbons each with two hydrogens and two extra to cap the ends (general formula : CnHn+2)
Ethylene (C2H4) has two carbons and four hydrogens making 6 atoms.
Following the formula CxH2x-2 where X is the number of carbons in the desired Alkyne, you should get C8H14 (i think.....)
Alkanes have the general formula of CnH2n+2 so for 12 carbons, that would be 2x12 + 2 = 26 hydrogen atoms.
Organic compounds are formed from carbon and hydrogen though sometimes there may be additional elements like oxygen, sulphur etc.carbon and hydrogen generally make hydrocarbon.hydrocarbons are also organic compounds.hydrocarbons are classified as alkanes , alkenes & alkynes.best example for hydrocarbon is methane...
In an alkane the number of hydrogen atoms is two greater than twice the number of carbon atoms. If we reverse this rule, we find that the number of carbon atoms is one less than half the number of hydrogen atoms. 32/2=16 16-1=15 So our alkane would have 15 carbon atoms. This alkane would be pentadecane or one of its isomers.
there are 8 hydrogen atoms present in propane. There is 8 hydrogen atoms in propane, Each carbon has a valency of 4, 4 bonds with other atoms. Hydrogen has valency of 1. the general formula for alkanes is CnH2n +2 (n means number of that atom.) so to find how many hydrogens there with, say, 50 carbons you would do CnH2n + 2= C50H102. :)
C6H12O6 is glucose. There are six carbons, twelve hydrogens and six oxygens in each molecule.
If it is saturated open chain hydrocarbon then hydrogen must be 244.
Oxaloacetic acid is C4H4O5 and has four carbons