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According to the balanced chemical equation, 3 liters of hydrogen is required to produce 2 liters of ammonia. So, for 12 liters of ammonia, you would need 18 liters of hydrogen. This is because the ratio of hydrogen to ammonia in the reaction is 3:2.
According to the balanced chemical equation, for every 1 mole of nitrogen gas (N2), 3 moles of hydrogen gas (H2) are needed. Since the volume of a gas is directly proportional to the number of moles, you would need 21 liters of hydrogen gas (3 times 7 liters) to react completely with 7 liters of nitrogen gas to produce ammonia.
All gasses: 12 L NH3 * [3H / 1NH3] * [1H2 / 2H] = 12*3/2 = 18 L H2
Since the reaction produces 2 moles of ammonia for every 3 moles of hydrogen used, the mole ratio is 3:2. Thus, for every 2 liters of ammonia, 3 liters of hydrogen are required. This means that (2/3) x L of hydrogen were used to produce L of ammonia in the Haber process at STP.
Assuming you are referring to the reaction of hydrogen and nitrogen to form ammonia, the balanced equation is: 3H2 + N2 → 2NH3 From the equation, 3 liters of hydrogen gas react with 1 liter of nitrogen gas. Therefore, if 6 liters of hydrogen gas are used, you would need 2 liters of nitrogen gas.
According to the balanced chemical equation, 3 liters of hydrogen is required to produce 2 liters of ammonia. So, for 12 liters of ammonia, you would need 18 liters of hydrogen. This is because the ratio of hydrogen to ammonia in the reaction is 3:2.
According to the balanced chemical equation, for every 1 mole of nitrogen gas (N2), 3 moles of hydrogen gas (H2) are needed. Since the volume of a gas is directly proportional to the number of moles, you would need 21 liters of hydrogen gas (3 times 7 liters) to react completely with 7 liters of nitrogen gas to produce ammonia.
When 1 liter of nitrogen gas reacts with 3 liters of hydrogen gas, they will react to produce 2 liters of ammonia gas. This follows the balanced chemical equation: N2 + 3H2 → 2NH3. Each mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
The molar ratio of hydrogen to ammonia in the Haber process is 3:2. Therefore, if 16 L of ammonia were produced, 24 L of hydrogen were used in the reaction.
All gasses: 12 L NH3 * [3H / 1NH3] * [1H2 / 2H] = 12*3/2 = 18 L H2
Since the reaction produces 2 moles of ammonia for every 3 moles of hydrogen used, the mole ratio is 3:2. Thus, for every 2 liters of ammonia, 3 liters of hydrogen are required. This means that (2/3) x L of hydrogen were used to produce L of ammonia in the Haber process at STP.
Assuming you are referring to the reaction of hydrogen and nitrogen to form ammonia, the balanced equation is: 3H2 + N2 → 2NH3 From the equation, 3 liters of hydrogen gas react with 1 liter of nitrogen gas. Therefore, if 6 liters of hydrogen gas are used, you would need 2 liters of nitrogen gas.
To determine the volume of hydrogen used in the Haber process to produce 16 mol of ammonia, we need to refer to the stoichiometry of the reaction. For every 3 mol of hydrogen used, 2 mol of ammonia are produced. Therefore, you would need to calculate the amount of hydrogen required based on this ratio. However, to convert moles to liters, you would need to know the conditions of pressure and temperature.
Ammonia has the chemical formula NH3, and thus there are three hydrogen atoms in a molecule of ammonia.
According to the balanced chemical equation, 3 moles of hydrogen are required to produce 2 moles of ammonia. As 22.4 liters of any gas at STP is equal to 1 mole, 1 mole of hydrogen gas occupies 22.4 liters. Therefore, to produce 18 liters of ammonia, (18/22.4) x 3 = 2.68 moles of hydrogen were used. This equates to 2.68 x 22.4 = 60.03 liters of hydrogen gas used during the reaction.
Ammonia is NH3. It has three hydrogens per molecule.
8 percent by volume of ammonia means you can multiply the total volume directly by the percentage of ammonia to get the answer.8 percent in decimal form is 0.08Total volume = 600 liters.Liters of ammonia = 600 liters * 0.08 = 48 liters