71.8 M
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
To determine the volume of NaOH solution needed to neutralize an acid solution, you would need to know the concentration of the acid solution and the volume of the acid solution. Using the equation n1V1 n2V2, where n represents the number of moles and V represents the volume, you can calculate the volume of NaOH solution needed.
To neutralize the acidic solution completely, you need to add a solution of basic nature. The volume of the basic solution required can be calculated using the formula: ( V_1 \times C_1 = V_2 \times C_2 ), where ( V_1 ) and ( C_1 ) are the volume and concentration of the acidic solution, and ( V_2 ) and ( C_2 ) are the volume and concentration of the basic solution, respectively. Substituting the known values, you can find the volume of the basic solution needed.
To determine the volume of potassium hydroxide solution needed to neutralize the hydrochloric acid solution, you can use the formula M1V1 = M2V2. By plugging in the given values, you can calculate the volume of the potassium hydroxide solution required. In this case, the volume of the 0.152 M potassium hydroxide solution needed to neutralize 10.2 ml of the 0.198 M hydrochloric acid solution would be 7.43 ml.
There is no chemical reaction between sod chloride solution and water, it would just dilute the sod chloride solution.
A concentration of 110 M or 106 M doesn't exist.
Molarity, not moles. Simple equality will do here.(0.200 M NaOH)(X milliliters) = (0.100 M H3PO4)(5.00 milliliters)0.200X = 0.5X = 2.5 milliliters sodium hydroxide solution needed====================================
0.0532
0.0932 L
129
To determine the volume of NaOH solution needed to neutralize an acid solution, you would need to know the concentration of the acid solution and the volume of the acid solution. Using the equation n1V1 n2V2, where n represents the number of moles and V represents the volume, you can calculate the volume of NaOH solution needed.
166
To neutralize the acidic solution completely, you need to add a solution of basic nature. The volume of the basic solution required can be calculated using the formula: ( V_1 \times C_1 = V_2 \times C_2 ), where ( V_1 ) and ( C_1 ) are the volume and concentration of the acidic solution, and ( V_2 ) and ( C_2 ) are the volume and concentration of the basic solution, respectively. Substituting the known values, you can find the volume of the basic solution needed.
To determine the volume of potassium hydroxide solution needed to neutralize the hydrochloric acid solution, you can use the formula M1V1 = M2V2. By plugging in the given values, you can calculate the volume of the potassium hydroxide solution required. In this case, the volume of the 0.152 M potassium hydroxide solution needed to neutralize 10.2 ml of the 0.198 M hydrochloric acid solution would be 7.43 ml.
There is no chemical reaction between sod chloride solution and water, it would just dilute the sod chloride solution.
The reaction between HNO3 and NaOH is a 1:1 molar ratio. This means that the moles of HNO3 required to neutralize the NaOH is the same as the moles of NaOH. Given that 20.0 ml of HNO3 is needed to neutralize 10.0 ml of a 1.67 M NaOH solution, the molarity of the HNO3 solution is twice the molarity of the NaOH solution, which is 3.34 M.
To find the volume of KOH solution needed to neutralize the acidic solution, you'll need to determine the moles of acid present and use the stoichiometry of the neutralization reaction. Calculate the moles of HCl and H2SO4 separately, and then find the limiting reactant. Finally, use the balanced chemical equation to determine the moles of KOH needed, which can then be converted to volume using the concentration of the KOH solution.